eCryptfs: Use DEFINE_MUTEX() for mutex lock

mutex lock can be initialized automatically with DEFINE_MUTEX()
rather than explicitly calling mutex_init().

Reported-by: Hulk Robot <hulkci@huawei.com>
Signed-off-by: Ye Bin <yebin10@huawei.com>
Signed-off-by: Tyler Hicks <code@tyhicks.com>
This commit is contained in:
Ye Bin 2021-04-09 17:51:42 +08:00 committed by Tyler Hicks
parent ffbed072be
commit 724fa86291

View File

@ -14,10 +14,10 @@
static LIST_HEAD(ecryptfs_msg_ctx_free_list);
static LIST_HEAD(ecryptfs_msg_ctx_alloc_list);
static struct mutex ecryptfs_msg_ctx_lists_mux;
static DEFINE_MUTEX(ecryptfs_msg_ctx_lists_mux);
static struct hlist_head *ecryptfs_daemon_hash;
struct mutex ecryptfs_daemon_hash_mux;
DEFINE_MUTEX(ecryptfs_daemon_hash_mux);
static int ecryptfs_hash_bits;
#define ecryptfs_current_euid_hash(uid) \
hash_long((unsigned long)from_kuid(&init_user_ns, current_euid()), ecryptfs_hash_bits)
@ -361,7 +361,6 @@ int __init ecryptfs_init_messaging(void)
"too large, defaulting to [%d] users\n", __func__,
ecryptfs_number_of_users);
}
mutex_init(&ecryptfs_daemon_hash_mux);
mutex_lock(&ecryptfs_daemon_hash_mux);
ecryptfs_hash_bits = 1;
while (ecryptfs_number_of_users >> ecryptfs_hash_bits)
@ -385,7 +384,6 @@ int __init ecryptfs_init_messaging(void)
rc = -ENOMEM;
goto out;
}
mutex_init(&ecryptfs_msg_ctx_lists_mux);
mutex_lock(&ecryptfs_msg_ctx_lists_mux);
ecryptfs_msg_counter = 0;
for (i = 0; i < ecryptfs_message_buf_len; i++) {