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[TCP]: Unite identical code from two seqno split blocks
Bogus seqno compares just mislead, the code is identical for both sides of the seqno compare (and was even executed just once because of return in between). Signed-off-by: Ilpo Järvinen <ilpo.jarvinen@helsinki.fi> Signed-off-by: Herbert Xu <herbert@gondor.apana.org.au> Signed-off-by: David S. Miller <davem@davemloft.net>
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@ -1246,8 +1246,7 @@ static int tcp_sacktag_one(struct sk_buff *skb, struct tcp_sock *tp,
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if (dup_sack && (sacked & TCPCB_RETRANS)) {
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if (after(TCP_SKB_CB(skb)->end_seq, tp->undo_marker))
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tp->undo_retrans--;
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if (!after(TCP_SKB_CB(skb)->end_seq, tp->snd_una) &&
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(sacked & TCPCB_SACKED_ACKED))
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if (sacked & TCPCB_SACKED_ACKED)
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*reord = min(fack_count, *reord);
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}
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@ -1310,10 +1309,6 @@ static int tcp_sacktag_one(struct sk_buff *skb, struct tcp_sock *tp,
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if (after(TCP_SKB_CB(skb)->seq, tcp_highest_sack_seq(tp)))
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tp->highest_sack = skb;
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} else {
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if (dup_sack && (sacked & TCPCB_RETRANS))
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*reord = min(fack_count, *reord);
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}
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/* D-SACK. We can detect redundant retransmission in S|R and plain R
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