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mq-deadline: make it clear that __dd_dispatch_request() works on all hw queues
Don't pass in the hardware queue to __dd_dispatch_request(), since it leads the reader to believe that we are returning a request for that specific hardware queue. That's not how mq-deadline works, the state for determining which request to serve next is shared across all hardware queues for a device. Reviewed-by: Omar Sandoval <osandov@fb.com> Reviewed-by: Ming Lei <ming.lei@redhat.com> Signed-off-by: Jens Axboe <axboe@kernel.dk>
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@ -267,9 +267,8 @@ deadline_next_request(struct deadline_data *dd, int data_dir)
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* deadline_dispatch_requests selects the best request according to
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* read/write expire, fifo_batch, etc
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*/
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static struct request *__dd_dispatch_request(struct blk_mq_hw_ctx *hctx)
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static struct request *__dd_dispatch_request(struct deadline_data *dd)
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{
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struct deadline_data *dd = hctx->queue->elevator->elevator_data;
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struct request *rq, *next_rq;
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bool reads, writes;
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int data_dir;
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@ -372,13 +371,19 @@ done:
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return rq;
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}
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/*
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* One confusing aspect here is that we get called for a specific
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* hardware queue, but we return a request that may not be for a
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* different hardware queue. This is because mq-deadline has shared
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* state for all hardware queues, in terms of sorting, FIFOs, etc.
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*/
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static struct request *dd_dispatch_request(struct blk_mq_hw_ctx *hctx)
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{
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struct deadline_data *dd = hctx->queue->elevator->elevator_data;
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struct request *rq;
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spin_lock(&dd->lock);
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rq = __dd_dispatch_request(hctx);
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rq = __dd_dispatch_request(dd);
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spin_unlock(&dd->lock);
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return rq;
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