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md: do_release_stripe(): No need to call md_wakeup_thread() twice
67f455486d
introduced a call to
md_wakeup_thread() when adding to the delayed_list. However the md
thread is woken up unconditionally just below.
Remove the unnecessary wakeup call.
Signed-off-by: Jes Sorensen <Jes.Sorensen@redhat.com>
Signed-off-by: NeilBrown <neilb@suse.de>
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parent
75aaf4c3e6
commit
ad3ab8b608
@ -296,12 +296,9 @@ static void do_release_stripe(struct r5conf *conf, struct stripe_head *sh,
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BUG_ON(atomic_read(&conf->active_stripes)==0);
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if (test_bit(STRIPE_HANDLE, &sh->state)) {
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if (test_bit(STRIPE_DELAYED, &sh->state) &&
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!test_bit(STRIPE_PREREAD_ACTIVE, &sh->state)) {
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!test_bit(STRIPE_PREREAD_ACTIVE, &sh->state))
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list_add_tail(&sh->lru, &conf->delayed_list);
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if (atomic_read(&conf->preread_active_stripes)
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< IO_THRESHOLD)
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md_wakeup_thread(conf->mddev->thread);
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} else if (test_bit(STRIPE_BIT_DELAY, &sh->state) &&
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else if (test_bit(STRIPE_BIT_DELAY, &sh->state) &&
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sh->bm_seq - conf->seq_write > 0)
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list_add_tail(&sh->lru, &conf->bitmap_list);
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else {
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