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locking/mutex: Document that mutex_unlock() is non-atomic
I have seen several cases of attempts to use mutex_unlock() to release an object such that the object can then be freed by another task. This is not safe because mutex_unlock(), in the MUTEX_FLAG_WAITERS && !MUTEX_FLAG_HANDOFF case, accesses the mutex structure after having marked it as unlocked; so mutex_unlock() requires its caller to ensure that the mutex stays alive until mutex_unlock() returns. If MUTEX_FLAG_WAITERS is set and there are real waiters, those waiters have to keep the mutex alive, but we could have a spurious MUTEX_FLAG_WAITERS left if an interruptible/killable waiter bailed between the points where __mutex_unlock_slowpath() did the cmpxchg reading the flags and where it acquired the wait_lock. ( With spinlocks, that kind of code pattern is allowed and, from what I remember, used in several places in the kernel. ) Document this, such a semantic difference between mutexes and spinlocks is fairly unintuitive. [ mingo: Made the changelog a bit more assertive, refined the comments. ] Signed-off-by: Jann Horn <jannh@google.com> Signed-off-by: Ingo Molnar <mingo@kernel.org> Link: https://lore.kernel.org/r/20231130204817.2031407-1-jannh@google.com
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@ -101,6 +101,12 @@ features that make lock debugging easier and faster:
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- Detects multi-task circular deadlocks and prints out all affected
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locks and tasks (and only those tasks).
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Releasing a mutex is not an atomic operation: Once a mutex release operation
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has begun, another context may be able to acquire the mutex before the release
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operation has fully completed. The mutex user must ensure that the mutex is not
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destroyed while a release operation is still in progress - in other words,
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callers of mutex_unlock() must ensure that the mutex stays alive until
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mutex_unlock() has returned.
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Interfaces
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----------
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@ -532,6 +532,11 @@ static noinline void __sched __mutex_unlock_slowpath(struct mutex *lock, unsigne
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* This function must not be used in interrupt context. Unlocking
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* of a not locked mutex is not allowed.
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*
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* The caller must ensure that the mutex stays alive until this function has
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* returned - mutex_unlock() can NOT directly be used to release an object such
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* that another concurrent task can free it.
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* Mutexes are different from spinlocks & refcounts in this aspect.
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*
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* This function is similar to (but not equivalent to) up().
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*/
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void __sched mutex_unlock(struct mutex *lock)
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