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x86: use kernel_stack_pointer() in kprobes.c
The way to obtain a kernel-mode stack pointer from a struct pt_regs in 32-bit mode is "subtle": the stack doesn't actually contain the stack pointer, but rather the location where it would have been marks the actual previous stack frame. For clarity, use kernel_stack_pointer() instead of coding this weirdness explicitly. Signed-off-by: H. Peter Anvin <hpa@zytor.com> Cc: Ananth N Mavinakayanahalli <ananth@in.ibm.com> Cc: Anil S Keshavamurthy <anil.s.keshavamurthy@intel.com> Cc: "David S. Miller" <davem@davemloft.net> Cc: Masami Hiramatsu <mhiramat@redhat.com>
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@ -60,19 +60,7 @@ void jprobe_return_end(void);
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DEFINE_PER_CPU(struct kprobe *, current_kprobe) = NULL;
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DEFINE_PER_CPU(struct kprobe_ctlblk, kprobe_ctlblk);
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#ifdef CONFIG_X86_64
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#define stack_addr(regs) ((unsigned long *)regs->sp)
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#else
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/*
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* "®s->sp" looks wrong, but it's correct for x86_32. x86_32 CPUs
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* don't save the ss and esp registers if the CPU is already in kernel
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* mode when it traps. So for kprobes, regs->sp and regs->ss are not
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* the [nonexistent] saved stack pointer and ss register, but rather
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* the top 8 bytes of the pre-int3 stack. So ®s->sp happens to
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* point to the top of the pre-int3 stack.
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*/
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#define stack_addr(regs) ((unsigned long *)®s->sp)
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#endif
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#define stack_addr(regs) ((unsigned long *)kernel_stack_pointer(regs))
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#define W(row, b0, b1, b2, b3, b4, b5, b6, b7, b8, b9, ba, bb, bc, bd, be, bf)\
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(((b0##UL << 0x0)|(b1##UL << 0x1)|(b2##UL << 0x2)|(b3##UL << 0x3) | \
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