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sched: Change usage of rt_rq->rt_se to rt_rq->tg->rt_se[cpu]
This is the first step to remove rt_rq member rt_se because it have the same meaning with tg->rt_se[cpu]. And the latter style is also used by the fair scheduling class. Signed-off-by: Yong Zhang <yong.zhang0@gmail.com> Cc: Rusty Russell <rusty@rustcorp.com.au> Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl> LKML-Reference: <2674af741001282257r28c97a92o9f90cf16fe8d3d84@mail.gmail.com> Signed-off-by: Ingo Molnar <mingo@elte.hu>
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@ -199,8 +199,11 @@ static void dequeue_rt_entity(struct sched_rt_entity *rt_se);
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static void sched_rt_rq_enqueue(struct rt_rq *rt_rq)
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{
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int this_cpu = smp_processor_id();
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struct task_struct *curr = rq_of_rt_rq(rt_rq)->curr;
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struct sched_rt_entity *rt_se = rt_rq->rt_se;
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struct sched_rt_entity *rt_se;
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rt_se = rt_rq->tg->rt_se[this_cpu];
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if (rt_rq->rt_nr_running) {
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if (rt_se && !on_rt_rq(rt_se))
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@ -212,7 +215,10 @@ static void sched_rt_rq_enqueue(struct rt_rq *rt_rq)
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static void sched_rt_rq_dequeue(struct rt_rq *rt_rq)
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{
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struct sched_rt_entity *rt_se = rt_rq->rt_se;
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int this_cpu = smp_processor_id();
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struct sched_rt_entity *rt_se;
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rt_se = rt_rq->tg->rt_se[this_cpu];
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if (rt_se && on_rt_rq(rt_se))
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dequeue_rt_entity(rt_se);
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