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habanalabs: correctly cast variable to __le32
When using the macro le32_to_cpu(x), we need to correctly convert x to be __le32 in case it is defined as u32 variable. Signed-off-by: Oded Gabbay <oded.gabbay@gmail.com> Reviewed-by: Tomer Tayar <ttayar@habana.ai>
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@ -1107,13 +1107,13 @@ void hl_wreg(struct hl_device *hdev, u32 reg, u32 val);
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mb(); \
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(val) = *((u32 *) (uintptr_t) (addr)); \
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if (mem_written_by_device) \
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(val) = le32_to_cpu(val); \
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(val) = le32_to_cpu(*(__le32 *) &(val)); \
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if (cond) \
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break; \
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if (timeout_us && ktime_compare(ktime_get(), __timeout) > 0) { \
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(val) = *((u32 *) (uintptr_t) (addr)); \
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if (mem_written_by_device) \
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(val) = le32_to_cpu(val); \
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(val) = le32_to_cpu(*(__le32 *) &(val)); \
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break; \
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} \
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if (sleep_us) \
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