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crypto: wait for a full jiffy in do_xor_speed
In the existing do_xor_speed(), there is no guarantee that we actually run do_2() for a full jiffy. We get the current jiffy, then run do_2() until the next jiffy. Instead, let's get the current jiffy, then wait until the next jiffy to start our test. Signed-off-by: Jim Kukunas <james.t.kukunas@linux.intel.com> Signed-off-by: NeilBrown <neilb@suse.de>
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@ -63,7 +63,7 @@ static void
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do_xor_speed(struct xor_block_template *tmpl, void *b1, void *b2)
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{
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int speed;
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unsigned long now;
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unsigned long now, j;
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int i, count, max;
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tmpl->next = template_list;
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@ -76,9 +76,11 @@ do_xor_speed(struct xor_block_template *tmpl, void *b1, void *b2)
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*/
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max = 0;
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for (i = 0; i < 5; i++) {
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now = jiffies;
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j = jiffies;
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count = 0;
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while (jiffies == now) {
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while ((now = jiffies) == j)
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cpu_relax();
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while (time_before(jiffies, now + 1)) {
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mb(); /* prevent loop optimzation */
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tmpl->do_2(BENCH_SIZE, b1, b2);
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mb();
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