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spi: fix double-free on spi_unregister_master
After 49dce689ad
, device_for_each_child
iteration hits the master device itself. Do not call spi_unregister_device()
for the master device.
Signed-off-by: Atsushi Nemoto <anemo@mba.ocn.ne.jp>
Acked-by: David Brownell <david-b@pacbell.net>
Cc: <stable@kernel.org>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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parent
cbff2fbf55
commit
350d0076c5
@ -457,10 +457,11 @@ done:
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EXPORT_SYMBOL_GPL(spi_register_master);
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static int __unregister(struct device *dev, void *unused)
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static int __unregister(struct device *dev, void *master_dev)
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{
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/* note: before about 2.6.14-rc1 this would corrupt memory: */
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spi_unregister_device(to_spi_device(dev));
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if (dev != master_dev)
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spi_unregister_device(to_spi_device(dev));
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return 0;
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}
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@ -478,7 +479,8 @@ void spi_unregister_master(struct spi_master *master)
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{
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int dummy;
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dummy = device_for_each_child(master->dev.parent, NULL, __unregister);
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dummy = device_for_each_child(master->dev.parent, &master->dev,
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__unregister);
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device_unregister(&master->dev);
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}
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EXPORT_SYMBOL_GPL(spi_unregister_master);
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