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xfs: delayed alloc blocks beyond EOF are valid after writeback
There is an assumption in the parts of XFS that flushing a dirty file will make all the delayed allocation blocks disappear from an inode. That is, that after calling xfs_flush_pages() then ip->i_delayed_blks will be zero. This is an invalid assumption as we may have specualtive preallocation beyond EOF and they are recorded in ip->i_delayed_blks. A flush of the dirty pages of an inode will not change the state of these blocks beyond EOF, so a non-zero deeelalloc block count after a flush is valid. The bmap code has an invalid ASSERT() that needs to be removed, and the swapext code has a bug in that while it swaps the data forks around, it fails to swap the i_delayed_blks counter associated with the fork and hence can get the block accounting wrong. Signed-off-by: Dave Chinner <dchinner@redhat.com> Reviewed-by: Christoph Hellwig <hch@lst.de>
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@ -5471,8 +5471,13 @@ xfs_getbmap(
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if (error)
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goto out_unlock_iolock;
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}
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ASSERT(ip->i_delayed_blks == 0);
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/*
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* even after flushing the inode, there can still be delalloc
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* blocks on the inode beyond EOF due to speculative
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* preallocation. These are not removed until the release
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* function is called or the inode is inactivated. Hence we
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* cannot assert here that ip->i_delayed_blks == 0.
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*/
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}
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lock = xfs_ilock_map_shared(ip);
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@ -377,6 +377,19 @@ xfs_swap_extents(
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ip->i_d.di_format = tip->i_d.di_format;
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tip->i_d.di_format = tmp;
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/*
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* The extents in the source inode could still contain speculative
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* preallocation beyond EOF (e.g. the file is open but not modified
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* while defrag is in progress). In that case, we need to copy over the
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* number of delalloc blocks the data fork in the source inode is
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* tracking beyond EOF so that when the fork is truncated away when the
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* temporary inode is unlinked we don't underrun the i_delayed_blks
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* counter on that inode.
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*/
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ASSERT(tip->i_delayed_blks == 0);
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tip->i_delayed_blks = ip->i_delayed_blks;
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ip->i_delayed_blks = 0;
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ilf_fields = XFS_ILOG_CORE;
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switch(ip->i_d.di_format) {
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