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slab: fix wrongly used macro
commit 'slab: restrict the number of objects in a slab' uses __builtin_constant_p() on #if macro. It is wrong usage of builtin function, but it is compiled on x86 without any problem, so I can't find it before 0 day build system find it. This commit fixes the situation by using KMALLOC_MIN_SIZE, instead of KMALLOC_SHIFT_LOW. KMALLOC_SHIFT_LOW is parsed to ilog2() on some architecture and this ilog2() uses __builtin_constant_p() and results in the problem. This problem would disappear by using KMALLOC_MIN_SIZE, since it is just constant. Tested-by: David Rientjes <rientjes@google.com> Signed-off-by: Joonsoo Kim <iamjoonsoo.kim@lge.com> Signed-off-by: Pekka Enberg <penberg@kernel.org>
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@ -201,17 +201,6 @@ struct kmem_cache {
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#ifndef KMALLOC_SHIFT_LOW
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#define KMALLOC_SHIFT_LOW 5
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#endif
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/*
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* This restriction comes from byte sized index implementation.
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* Page size is normally 2^12 bytes and, in this case, if we want to use
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* byte sized index which can represent 2^8 entries, the size of the object
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* should be equal or greater to 2^12 / 2^8 = 2^4 = 16.
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* If minimum size of kmalloc is less than 16, we use it as minimum object
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* size and give up to use byte sized index.
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*/
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#define SLAB_OBJ_MIN_SIZE (KMALLOC_SHIFT_LOW < 4 ? \
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(1 << KMALLOC_SHIFT_LOW) : 16)
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#endif
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#ifdef CONFIG_SLUB
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@ -253,6 +242,17 @@ struct kmem_cache {
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#define KMALLOC_MIN_SIZE (1 << KMALLOC_SHIFT_LOW)
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#endif
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/*
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* This restriction comes from byte sized index implementation.
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* Page size is normally 2^12 bytes and, in this case, if we want to use
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* byte sized index which can represent 2^8 entries, the size of the object
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* should be equal or greater to 2^12 / 2^8 = 2^4 = 16.
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* If minimum size of kmalloc is less than 16, we use it as minimum object
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* size and give up to use byte sized index.
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*/
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#define SLAB_OBJ_MIN_SIZE (KMALLOC_MIN_SIZE < 16 ? \
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(KMALLOC_MIN_SIZE) : 16)
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#ifndef CONFIG_SLOB
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extern struct kmem_cache *kmalloc_caches[KMALLOC_SHIFT_HIGH + 1];
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#ifdef CONFIG_ZONE_DMA
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