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Btrfs: use RCU instead of a spinlock to protect the root node
The pointer to the extent buffer for the root of each tree is protected by a spinlock so that we can safely read the pointer and take a reference on the extent buffer. But now that the extent buffers are freed via RCU, we can safely use rcu_read_lock instead. Signed-off-by: Chris Mason <chris.mason@oracle.com>
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@ -147,10 +147,11 @@ noinline void btrfs_release_path(struct btrfs_root *root, struct btrfs_path *p)
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struct extent_buffer *btrfs_root_node(struct btrfs_root *root)
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{
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struct extent_buffer *eb;
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spin_lock(&root->node_lock);
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eb = root->node;
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rcu_read_lock();
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eb = rcu_dereference(root->node);
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extent_buffer_get(eb);
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spin_unlock(&root->node_lock);
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rcu_read_unlock();
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return eb;
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}
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@ -165,14 +166,8 @@ struct extent_buffer *btrfs_lock_root_node(struct btrfs_root *root)
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while (1) {
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eb = btrfs_root_node(root);
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btrfs_tree_lock(eb);
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spin_lock(&root->node_lock);
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if (eb == root->node) {
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spin_unlock(&root->node_lock);
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if (eb == root->node)
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break;
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}
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spin_unlock(&root->node_lock);
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btrfs_tree_unlock(eb);
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free_extent_buffer(eb);
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}
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@ -458,10 +453,8 @@ static noinline int __btrfs_cow_block(struct btrfs_trans_handle *trans,
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else
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parent_start = 0;
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spin_lock(&root->node_lock);
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root->node = cow;
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extent_buffer_get(cow);
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spin_unlock(&root->node_lock);
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rcu_assign_pointer(root->node, cow);
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btrfs_free_tree_block(trans, root, buf, parent_start,
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last_ref);
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@ -930,9 +923,7 @@ static noinline int balance_level(struct btrfs_trans_handle *trans,
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goto enospc;
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}
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spin_lock(&root->node_lock);
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root->node = child;
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spin_unlock(&root->node_lock);
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rcu_assign_pointer(root->node, child);
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add_root_to_dirty_list(root);
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btrfs_tree_unlock(child);
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@ -2007,10 +1998,8 @@ static noinline int insert_new_root(struct btrfs_trans_handle *trans,
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btrfs_mark_buffer_dirty(c);
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spin_lock(&root->node_lock);
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old = root->node;
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root->node = c;
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spin_unlock(&root->node_lock);
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rcu_assign_pointer(root->node, c);
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/* the super has an extra ref to root->node */
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free_extent_buffer(old);
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