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usb: usbip: vudc: fix left shift overflow
In v_recv_cmd_submit(), urb_p->urb->pipe has the type unsigned int
(which is 32-bit long on x86_64) but 11<<30 results in a 34-bit integer.
Therefore the 2 leading bits are truncated and
urb_p->urb->pipe &= ~(11 << 30);
has the same meaning as
urb_p->urb->pipe &= ~(3 << 30);
This second statement seems to be how the code was intended to be
written, as PIPE_ constants have values between 0 and 3.
The overflow has been detected with a clang warning:
drivers/usb/usbip/vudc_rx.c:145:27: warning: signed shift result
(0x2C0000000) requires 35 bits to represent, but 'int' only has 32
bits [-Wshift-overflow]
urb_p->urb->pipe &= ~(11 << 30);
~~ ^ ~~
Fixes: 79c02cb1fd
("usbip: vudc: Add vudc_rx")
Signed-off-by: Nicolas Iooss <nicolas.iooss_linux@m4x.org>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
parent
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@ -142,7 +142,7 @@ static int v_recv_cmd_submit(struct vudc *udc,
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urb_p->urb->status = -EINPROGRESS;
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/* FIXME: more pipe setup to please usbip_common */
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urb_p->urb->pipe &= ~(11 << 30);
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urb_p->urb->pipe &= ~(3 << 30);
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switch (urb_p->ep->type) {
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case USB_ENDPOINT_XFER_BULK:
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urb_p->urb->pipe |= (PIPE_BULK << 30);
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