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i40evf: invite vector 0 to the interrupt party
The i40evf_irq_enable and i40evf_fire_sw_interrupt functions were unfairly discriminating against MSI-X vector 0, just because it doesn't handle traffic. That doesn't mean it's not essential to the operation of the driver. This change allows the watchdog to fire vector 0 via software, which makes the driver tolerant of dropped interrupts on that vector. Buck up, vector 0! You can be part of our gang! Change-ID: I37131d955018a6b3e711e1732d21428acd0d767e Signed-off-by: Mitch Williams <mitch.a.williams@intel.com> Tested-by: Jim Young <jamesx.m.young@intel.com> Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
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@ -260,6 +260,12 @@ static void i40evf_fire_sw_int(struct i40evf_adapter *adapter,
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int i;
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uint32_t dyn_ctl;
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if (mask & 1) {
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dyn_ctl = rd32(hw, I40E_VFINT_DYN_CTL01);
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dyn_ctl |= I40E_VFINT_DYN_CTLN_SWINT_TRIG_MASK |
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I40E_VFINT_DYN_CTLN_CLEARPBA_MASK;
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wr32(hw, I40E_VFINT_DYN_CTL01, dyn_ctl);
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}
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for (i = 1; i < adapter->num_msix_vectors; i++) {
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if (mask & (1 << i)) {
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dyn_ctl = rd32(hw, I40E_VFINT_DYN_CTLN1(i - 1));
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@ -278,6 +284,7 @@ void i40evf_irq_enable(struct i40evf_adapter *adapter, bool flush)
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{
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struct i40e_hw *hw = &adapter->hw;
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i40evf_misc_irq_enable(adapter);
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i40evf_irq_enable_queues(adapter, ~0);
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if (flush)
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