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power: supply: core: Fix boundary conditions in interpolation
The functions power_supply_temp2resist_simple and power_supply_ocv2cap_simple handle boundary conditions incorrectly. The change was introduced ina4585ba205
("power: supply: core: Use library interpolation"). There are two issues: First, the lines "high = i - 1" and "high = i" in ocv2cap have the wrong order compared to temp2resist. As a consequence, ocv2cap sets high=-1 if ocv>table[0].ocv, which causes an out-of-bounds read. Second, the logic of temp2resist is also not correct. Consider the case table[] = {{20, 100}, {10, 80}, {0, 60}}. For temp=5, we expect a resistance of 70% by interpolation. However, temp2resist sets high=low=2 and returns 60. Cc: stable@vger.kernel.org Signed-off-by: Dorian Rudolph <mail@dorianrudolph.com> Reviewed-by: Linus Walleij <linus.walleij@linaro.org> Fixes:a4585ba205
("power: supply: core: Use library interpolation") Signed-off-by: Sebastian Reichel <sebastian.reichel@collabora.com>
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@ -846,17 +846,17 @@ int power_supply_temp2resist_simple(struct power_supply_resistance_temp_table *t
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{
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int i, high, low;
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/* Break loop at table_len - 1 because that is the highest index */
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for (i = 0; i < table_len - 1; i++)
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for (i = 0; i < table_len; i++)
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if (temp > table[i].temp)
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break;
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/* The library function will deal with high == low */
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if ((i == 0) || (i == (table_len - 1)))
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high = i;
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if (i == 0)
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high = low = i;
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else if (i == table_len)
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high = low = i - 1;
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else
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high = i - 1;
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low = i;
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high = (low = i) - 1;
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return fixp_linear_interpolate(table[low].temp,
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table[low].resistance,
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@ -958,17 +958,17 @@ int power_supply_ocv2cap_simple(struct power_supply_battery_ocv_table *table,
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{
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int i, high, low;
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/* Break loop at table_len - 1 because that is the highest index */
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for (i = 0; i < table_len - 1; i++)
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for (i = 0; i < table_len; i++)
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if (ocv > table[i].ocv)
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break;
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/* The library function will deal with high == low */
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if ((i == 0) || (i == (table_len - 1)))
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high = i - 1;
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if (i == 0)
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high = low = i;
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else if (i == table_len)
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high = low = i - 1;
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else
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high = i; /* i.e. i == 0 */
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low = i;
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high = (low = i) - 1;
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return fixp_linear_interpolate(table[low].ocv,
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table[low].capacity,
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