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x86, vdso: Error out if the vdso contains external references
The vdso is a piece of userspace code which is supposed to be fully self-contained. Any external (undefined) reference is an error, and should be caught at compile time. This was giving us trouble when compiling with -Os on gcc 4.5.0, for example (failed inline). The need to do a buildtime check was pointed out by Andi Kleen. Reported-by: Andi Kleen <andi@firstfloor.org> LKML-Reference: <tip-*@vger.kernel.org> Signed-off-by: H. Peter Anvin <hpa@linux.intel.com>
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@ -120,7 +120,8 @@ $(obj)/vdso32-syms.lds: $(vdso32.so-y:%=$(obj)/vdso32-%-syms.lds) FORCE
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quiet_cmd_vdso = VDSO $@
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cmd_vdso = $(CC) -nostdlib -o $@ \
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$(VDSO_LDFLAGS) $(VDSO_LDFLAGS_$(filter %.lds,$(^F))) \
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-Wl,-T,$(filter %.lds,$^) $(filter %.o,$^)
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-Wl,-T,$(filter %.lds,$^) $(filter %.o,$^) && \
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sh $(srctree)/$(src)/checkundef.sh '$(NM)' '$@'
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VDSO_LDFLAGS = -fPIC -shared $(call cc-ldoption, -Wl$(comma)--hash-style=sysv)
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GCOV_PROFILE := n
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10
arch/x86/vdso/checkundef.sh
Executable file
10
arch/x86/vdso/checkundef.sh
Executable file
@ -0,0 +1,10 @@
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#!/bin/sh
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nm="$1"
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file="$2"
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"$nm" "$file" | grep '^ *U' > /dev/null 2>&1
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if [ $? -eq 1 ]; then
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exit 0
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else
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echo "$file: undefined symbols found" >&2
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exit 1
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fi
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