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qemu-io: Fix handling of bdrv_is_allocated() return value (Kevin Wolf)

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bdrv_is_allocated() returns a boolean which indicates if the offset is
allocated, not 0 on success and everything else is an error.

Signed-off-by: Kevin Wolf <kwolf@redhat.com>
Signed-off-by: Anthony Liguori <aliguori@us.ibm.com>


git-svn-id: svn://svn.savannah.nongnu.org/qemu/trunk@7181 c046a42c-6fe2-441c-8c8c-71466251a162
This commit is contained in:
aliguori 2009-04-18 15:36:19 +00:00
parent cd33feecb3
commit 838ab728bf
1 changed files with 5 additions and 7 deletions
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12
qemu-io.c
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@ -794,6 +794,7 @@ alloc_f(int argc, char **argv)
char s1[64];
int num;
int ret;
const char *retstr;
offset = cvtnum(argv[1]);
if (offset & 0x1ff) {
@ -808,18 +809,15 @@ alloc_f(int argc, char **argv)
nb_sectors = 1;
ret = bdrv_is_allocated(bs, offset >> 9, nb_sectors, &num);
if (ret) {
printf("is_allocated: %s", strerror(ret));
return 0;
}
cvtstr(offset, s1, sizeof(s1));
retstr = ret ? "allocated" : "not allocated";
if (nb_sectors == 1)
printf("sector allocated at offset %s\n", s1);
printf("sector %s at offset %s\n", retstr, s1);
else
printf("%d/%d sectors allocated at offset %s\n",
num, nb_sectors, s1);
printf("%d/%d sectors %s at offset %s\n",
num, nb_sectors, retstr, s1);
return 0;
}