libqtest: Wait for the right child PID after killing QEMU

When running "make check" with gcov enabled, we get the following
message:

   hw/tmp105.gcda:cannot open data file, assuming not executed

The problem happens because:

 * tmp105-test exits before QEMU exits, because waitpid() at
   qtest_quit() fails;
 * waitpid() fails because there's another process already
   waiting for the QEMU process;
 * The process that is already waiting for QEMU is the child created by
   qtest_init() to run system();
 * qtest_quit() is incorrectly waiting for the QEMU PID directly instead
   of the child created by qtest_init().

This fixes the problem by sending SIGTERM to QEMU, but waiting for the
child process created by qtest_init() (that exits immediately after QEMU
exits).

Reported-by: Andreas Färber <afaerber@suse.de>
Signed-off-by: Eduardo Habkost <ehabkost@redhat.com>
Signed-off-by: Anthony Liguori <aliguori@us.ibm.com>
This commit is contained in:
Eduardo Habkost 2013-01-28 16:15:16 -02:00 committed by Anthony Liguori
parent 3e7b8f4e6f
commit 6bf0076643

View File

@ -39,7 +39,8 @@ struct QTestState
int qmp_fd;
bool irq_level[MAX_IRQ];
GString *rx;
gchar *pid_file;
gchar *pid_file; /* QEMU PID file */
int child_pid; /* Child process created to execute QEMU */
char *socket_path, *qmp_socket_path;
};
@ -144,6 +145,7 @@ QTestState *qtest_init(const char *extra_args)
s->rx = g_string_new("");
s->pid_file = pid_file;
s->child_pid = pid;
for (i = 0; i < MAX_IRQ; i++) {
s->irq_level[i] = false;
}
@ -165,8 +167,9 @@ void qtest_quit(QTestState *s)
pid_t pid = qtest_qemu_pid(s);
if (pid != -1) {
/* kill QEMU, but wait for the child created by us to run system() */
kill(pid, SIGTERM);
waitpid(pid, &status, 0);
waitpid(s->child_pid, &status, 0);
}
unlink(s->pid_file);