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target/i386: fix fbstp handling of negative zero
The fbstp implementation stores +0 when the rounded result should be -0 because it compares an integer value with 0 to determine the sign. Fix this by checking the sign bit of the operand instead. Signed-off-by: Joseph Myers <joseph@codesourcery.com> Message-Id: <alpine.DEB.2.21.2005132350230.11687@digraph.polyomino.org.uk> Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
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@ -726,11 +726,14 @@ void helper_fbst_ST0(CPUX86State *env, target_ulong ptr)
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int v;
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target_ulong mem_ref, mem_end;
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int64_t val;
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CPU_LDoubleU temp;
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temp.d = ST0;
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val = floatx80_to_int64(ST0, &env->fp_status);
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mem_ref = ptr;
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mem_end = mem_ref + 9;
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if (val < 0) {
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if (SIGND(temp)) {
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cpu_stb_data_ra(env, mem_end, 0x80, GETPC());
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val = -val;
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} else {
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25
tests/tcg/i386/test-i386-fbstp.c
Normal file
25
tests/tcg/i386/test-i386-fbstp.c
Normal file
@ -0,0 +1,25 @@
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/* Test fbstp instruction. */
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#include <stdio.h>
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#include <string.h>
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int main(void)
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{
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int ret = 0;
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unsigned char out[10];
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memset(out, 0xfe, sizeof out);
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__asm__ volatile ("fbstp %0" : "=m" (out) : "t" (-0.0L) : "st");
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out[9] &= 0x80;
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if (memcmp(out, "\0\0\0\0\0\0\0\0\0\x80", sizeof out) != 0) {
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printf("FAIL: fbstp -0\n");
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ret = 1;
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}
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memset(out, 0x12, sizeof out);
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__asm__ volatile ("fbstp %0" : "=m" (out) : "t" (-0.1L) : "st");
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out[9] &= 0x80;
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if (memcmp(out, "\0\0\0\0\0\0\0\0\0\x80", sizeof out) != 0) {
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printf("FAIL: fbstp -0.1\n");
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ret = 1;
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}
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return ret;
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}
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