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0998fcd804
the function return the symbolic hebrew name. (Patch by Moshe Doron <mosdoron@netvision.net.il>) @- Added an aditional parameter to the jdtojewish() function which makes @ the function return the symbolic hebrew name. (Moshe Doron, Derick)
760 lines
25 KiB
C
760 lines
25 KiB
C
/* $selId: jewish.c,v 2.0 1995/10/24 01:13:06 lees Exp $
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* Copyright 1993-1995, Scott E. Lee, all rights reserved.
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* Permission granted to use, copy, modify, distribute and sell so long as
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* the above copyright and this permission statement are retained in all
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* copies. THERE IS NO WARRANTY - USE AT YOUR OWN RISK.
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*/
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/**************************************************************************
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*
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* These are the externally visible components of this file:
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*
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* void
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* SdnToJewish(
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* long int sdn,
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* int *pYear,
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* int *pMonth,
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* int *pDay);
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*
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* Convert a SDN to a Jewish calendar date. If the input SDN is before the
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* first day of year 1, the three output values will all be set to zero,
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* otherwise *pYear will be > 0; *pMonth will be in the range 1 to 13
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* inclusive; *pDay will be in the range 1 to 30 inclusive. Note that Adar
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* II is assigned the month number 7 and Elul is always 13.
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*
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* long int
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* JewishToSdn(
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* int year,
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* int month,
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* int day);
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*
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* Convert a Jewish calendar date to a SDN. Zero is returned when the
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* input date is detected as invalid or out of the supported range. The
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* return value will be > 0 for all valid, supported dates, but there are
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* some invalid dates that will return a positive value. To verify that a
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* date is valid, convert it to SDN and then back and compare with the
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* original.
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*
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* char *JewishMonthName[14];
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*
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* Convert a Jewish month number (1 to 13) to the name of the Jewish month
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* (null terminated). An index of zero will return a zero length string.
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*
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* VALID RANGE
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*
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* Although this software can handle dates all the way back to the year
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* 1 (3761 B.C.), such use may not be meaningful.
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*
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* The Jewish calendar has been in use for several thousand years, but
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* in the early days there was no formula to determine the start of a
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* month. A new month was started when the new moon was first
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* observed.
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*
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* It is not clear when the current rule based calendar replaced the
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* observation based calendar. According to the book "Jewish Calendar
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* Mystery Dispelled" by George Zinberg, the patriarch Hillel II
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* published these rules in 358 A.D. But, according to The
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* Encyclopedia Judaica, Hillel II may have only published the 19 year
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* rule for determining the occurrence of leap years.
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*
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* I have yet to find a specific date when the current set of rules
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* were known to be in use.
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*
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* CALENDAR OVERVIEW
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*
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* The Jewish calendar is based on lunar as well as solar cycles. A
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* month always starts on or near a new moon and has either 29 or 30
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* days (a lunar cycle is about 29 1/2 days). Twelve of these
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* alternating 29-30 day months gives a year of 354 days, which is
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* about 11 1/4 days short of a solar year.
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*
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* Since a month is defined to be a lunar cycle (new moon to new moon),
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* this 11 1/4 day difference cannot be overcome by adding days to a
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* month as with the Gregorian calendar, so an entire month is
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* periodically added to the year, making some years 13 months long.
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*
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* For astronomical as well as ceremonial reasons, the start of a new
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* year may be delayed until a day or two after the new moon causing
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* years to vary in length. Leap years can be from 383 to 385 days and
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* common years can be from 353 to 355 days. These are the months of
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* the year and their possible lengths:
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*
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* COMMON YEAR LEAP YEAR
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* 1 Tishri 30 30 30 30 30 30
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* 2 Heshvan 29 29 30 29 29 30 (variable)
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* 3 Kislev 29 30 30 29 30 30 (variable)
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* 4 Tevet 29 29 29 29 29 29
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* 5 Shevat 30 30 30 30 30 30
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* 6 Adar I 29 29 29 30 30 30 (variable)
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* 7 Adar II -- -- -- 29 29 29 (optional)
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* 8 Nisan 30 30 30 30 30 30
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* 9 Iyyar 29 29 29 29 29 29
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* 10 Sivan 30 30 30 30 30 30
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* 11 Tammuz 29 29 29 29 29 29
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* 12 Av 30 30 30 30 30 30
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* 13 Elul 29 29 29 29 29 29
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* --- --- --- --- --- ---
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* 353 354 355 383 384 385
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*
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* Note that the month names and other words that appear in this file
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* have multiple possible spellings in the Roman character set. I have
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* chosen to use the spellings found in the Encyclopedia Judaica.
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*
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* Adar II, the month added for leap years, is sometimes referred to as
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* the 13th month, but I have chosen to assign it the number 7 to keep
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* the months in chronological order. This may not be consistent with
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* other numbering schemes.
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*
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* Leap years occur in a fixed pattern of 19 years called the metonic
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* cycle. The 3rd, 6th, 8th, 11th, 14th, 17th and 19th years of this
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* cycle are leap years. The first metonic cycle starts with Jewish
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* year 1, or 3761/60 B.C. This is believed to be the year of
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* creation.
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*
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* To construct the calendar for a year, you must first find the length
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* of the year by determining the first day of the year (Tishri 1, or
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* Rosh Ha-Shanah) and the first day of the following year. This
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* selects one of the six possible month length configurations listed
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* above.
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*
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* Finding the first day of the year is the most difficult part.
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* Finding the date and time of the new moon (or molad) is the first
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* step. For this purpose, the lunar cycle is assumed to be 29 days 12
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* hours and 793 halakim. A halakim is 1/1080th of an hour or 3 1/3
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* seconds. (This assumed value is only about 1/2 second less than the
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* value used by modern astronomers -- not bad for a number that was
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* determined so long ago.) The first molad of year 1 occurred on
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* Sunday at 11:20:11 P.M. This would actually be Monday, because the
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* Jewish day is considered to begin at sunset.
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*
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* Since sunset varies, the day is assumed to begin at 6:00 P.M. for
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* calendar calculation purposes. So, the first molad was 5 hours 793
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* halakim after the start of Tishri 1, 0001 (which was Monday
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* September 7, 4761 B.C. by the Gregorian calendar). All subsequent
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* molads can be calculated from this starting point by adding the
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* length of a lunar cycle.
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*
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* Once the molad that starts a year is determined the actual start of
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* the year (Tishri 1) can be determined. Tishri 1 will be the day of
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* the molad unless it is delayed by one of the following four rules
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* (called dehiyyot). Each rule can delay the start of the year by one
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* day, and since rule #1 can combine with one of the other rules, it
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* can be delayed as much as two days.
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*
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* 1. Tishri 1 must never be Sunday, Wednesday or Friday. (This
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* is largely to prevent certain holidays from occurring on the
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* day before or after the Sabbath.)
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*
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* 2. If the molad occurs on or after noon, Tishri 1 must be
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* delayed.
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*
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* 3. If it is a common (not leap) year and the molad occurs on
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* Tuesday at or after 3:11:20 A.M., Tishri 1 must be delayed.
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*
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* 4. If it is the year following a leap year and the molad occurs
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* on Monday at or after 9:32:43 and 1/3 sec, Tishri 1 must be
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* delayed.
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*
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* GLOSSARY
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*
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* dehiyyot The set of 4 rules that determine when the new year
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* starts relative to the molad.
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*
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* halakim 1/1080th of an hour or 3 1/3 seconds.
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*
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* lunar cycle The period of time between mean conjunctions of the
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* sun and moon (new moon to new moon). This is
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* assumed to be 29 days 12 hours and 793 halakim for
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* calendar purposes.
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*
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* metonic cycle A 19 year cycle which determines which years are
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* leap years and which are common years. The 3rd,
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* 6th, 8th, 11th, 14th, 17th and 19th years of this
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* cycle are leap years.
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*
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* molad The date and time of the mean conjunction of the
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* sun and moon (new moon). This is the approximate
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* beginning of a month.
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*
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* Rosh Ha-Shanah The first day of the Jewish year (Tishri 1).
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*
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* Tishri The first month of the Jewish year.
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*
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* ALGORITHMS
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*
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* SERIAL DAY NUMBER TO JEWISH DATE
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*
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* The simplest approach would be to use the rules stated above to find
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* the molad of Tishri before and after the given day number. Then use
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* the molads to find Tishri 1 of the current and following years.
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* From this the length of the year can be determined and thus the
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* length of each month. But this method is used as a last resort.
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*
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* The first 59 days of the year are the same regardless of the length
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* of the year. As a result, only the day number of the start of the
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* year is required.
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*
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* Similarly, the last 6 months do not change from year to year. And
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* since it can be determined whether the year is a leap year by simple
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* division, the lengths of Adar I and II can be easily calculated. In
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* fact, all dates after the 3rd month are consistent from year to year
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* (once it is known whether it is a leap year).
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*
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* This means that if the given day number falls in the 3rd month or on
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* the 30th day of the 2nd month the length of the year must be found,
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* but in no other case.
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*
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* So, the approach used is to take the given day number and round it
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* to the closest molad of Tishri (first new moon of the year). The
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* rounding is not really to the *closest* molad, but is such that if
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* the day number is before the middle of the 3rd month the molad at
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* the start of the year is found, otherwise the molad at the end of
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* the year is found.
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*
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* Only if the day number is actually found to be in the ambiguous
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* period of 29 to 31 days is the other molad calculated.
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*
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* JEWISH DATE TO SERIAL DAY NUMBER
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*
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* The year number is used to find which 19 year metonic cycle contains
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* the date and which year within the cycle (this is a division and
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* modulus). This also determines whether it is a leap year.
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*
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* If the month is 1 or 2, the calculation is simple addition to the
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* first of the year.
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*
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* If the month is 8 (Nisan) or greater, the calculation is simple
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* subtraction from beginning of the following year.
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*
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* If the month is 4 to 7, it is considered whether it is a leap year
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* and then simple subtraction from the beginning of the following year
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* is used.
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*
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* Only if it is the 3rd month is both the start and end of the year
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* required.
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*
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* TESTING
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*
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* This algorithm has been tested in two ways. First, 510 dates from a
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* table in "Jewish Calendar Mystery Dispelled" were calculated and
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* compared to the table. Second, the calculation algorithm described
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* in "Jewish Calendar Mystery Dispelled" was coded and used to verify
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* all dates from the year 1 (3761 B.C.) to the year 13760 (10000
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* A.D.).
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*
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* The source code of the verification program is included in this
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* package.
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*
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* REFERENCES
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*
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* The Encyclopedia Judaica, the entry for "Calendar"
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*
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* The Jewish Encyclopedia
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*
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* Jewish Calendar Mystery Dispelled by George Zinberg, Vantage Press,
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* 1963
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*
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* The Comprehensive Hebrew Calendar by Arthur Spier, Behrman House
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*
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* The Book of Calendars [note that this work contains many typos]
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*
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**************************************************************************/
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#include "sdncal.h"
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#define HALAKIM_PER_HOUR 1080
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#define HALAKIM_PER_DAY 25920
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#define HALAKIM_PER_LUNAR_CYCLE ((29 * HALAKIM_PER_DAY) + 13753)
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#define HALAKIM_PER_METONIC_CYCLE (HALAKIM_PER_LUNAR_CYCLE * (12 * 19 + 7))
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#define JEWISH_SDN_OFFSET 347997
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#define NEW_MOON_OF_CREATION 31524
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#define SUNDAY 0
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#define MONDAY 1
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#define TUESDAY 2
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#define WEDNESDAY 3
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#define THURSDAY 4
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#define FRIDAY 5
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#define SATURDAY 6
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#define NOON (18 * HALAKIM_PER_HOUR)
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#define AM3_11_20 ((9 * HALAKIM_PER_HOUR) + 204)
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#define AM9_32_43 ((15 * HALAKIM_PER_HOUR) + 589)
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static int monthsPerYear[19] =
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{
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12, 12, 13, 12, 12, 13, 12, 13, 12, 12, 13, 12, 12, 13, 12, 12, 13, 12, 13
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};
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static int yearOffset[19] =
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{
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0, 12, 24, 37, 49, 61, 74, 86, 99, 111, 123,
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136, 148, 160, 173, 185, 197, 210, 222
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};
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char *JewishMonthName[14] =
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{
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"",
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"Tishri",
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"Heshvan",
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"Kislev",
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"Tevet",
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"Shevat",
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"AdarI",
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"AdarII",
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"Nisan",
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"Iyyar",
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"Sivan",
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"Tammuz",
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"Av",
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"Elul"
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};
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char *JewishMonthHebName[14] =
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{
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"",
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"<EFBFBD><EFBFBD><EFBFBD><EFBFBD>",
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"<EFBFBD><EFBFBD><EFBFBD><EFBFBD>",
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"<EFBFBD><EFBFBD><EFBFBD><EFBFBD>",
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"<EFBFBD><EFBFBD><EFBFBD>",
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"<EFBFBD><EFBFBD><EFBFBD>",
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"<EFBFBD><EFBFBD><EFBFBD>",
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"'<27><><EFBFBD> <20>",
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"<EFBFBD><EFBFBD><EFBFBD><EFBFBD>",
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"<EFBFBD><EFBFBD><EFBFBD><EFBFBD>",
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"<EFBFBD><EFBFBD><EFBFBD><EFBFBD>",
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"<EFBFBD><EFBFBD><EFBFBD><EFBFBD>",
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"<EFBFBD><EFBFBD>",
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"<EFBFBD><EFBFBD><EFBFBD><EFBFBD>"
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};
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/************************************************************************
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* Given the year within the 19 year metonic cycle and the time of a molad
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* (new moon) which starts that year, this routine will calculate what day
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* will be the actual start of the year (Tishri 1 or Rosh Ha-Shanah). This
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* first day of the year will be the day of the molad unless one of 4 rules
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* (called dehiyyot) delays it. These 4 rules can delay the start of the
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* year by as much as 2 days.
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*/
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static long int Tishri1(
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int metonicYear,
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long int moladDay,
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long int moladHalakim)
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{
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long int tishri1;
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int dow;
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int leapYear;
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int lastWasLeapYear;
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tishri1 = moladDay;
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dow = tishri1 % 7;
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leapYear = metonicYear == 2 || metonicYear == 5 || metonicYear == 7
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|| metonicYear == 10 || metonicYear == 13 || metonicYear == 16
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|| metonicYear == 18;
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lastWasLeapYear = metonicYear == 3 || metonicYear == 6
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|| metonicYear == 8 || metonicYear == 11 || metonicYear == 14
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|| metonicYear == 17 || metonicYear == 0;
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/* Apply rules 2, 3 and 4. */
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if ((moladHalakim >= NOON) ||
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((!leapYear) && dow == TUESDAY && moladHalakim >= AM3_11_20) ||
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(lastWasLeapYear && dow == MONDAY && moladHalakim >= AM9_32_43)) {
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tishri1++;
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dow++;
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if (dow == 7) {
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dow = 0;
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}
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}
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/* Apply rule 1 after the others because it can cause an additional
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* delay of one day. */
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if (dow == WEDNESDAY || dow == FRIDAY || dow == SUNDAY) {
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tishri1++;
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}
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return (tishri1);
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}
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/************************************************************************
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* Given a metonic cycle number, calculate the date and time of the molad
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* (new moon) that starts that cycle. Since the length of a metonic cycle
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* is a constant, this is a simple calculation, except that it requires an
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* intermediate value which is bigger that 32 bits. Because this
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* intermediate value only needs 36 to 37 bits and the other numbers are
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* constants, the process has been reduced to just a few steps.
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*/
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static void MoladOfMetonicCycle(
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int metonicCycle,
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long int *pMoladDay,
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long int *pMoladHalakim)
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{
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register unsigned long int r1, r2, d1, d2;
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/* Start with the time of the first molad after creation. */
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r1 = NEW_MOON_OF_CREATION;
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/* Calculate metonicCycle * HALAKIM_PER_METONIC_CYCLE. The upper 32
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* bits of the result will be in r2 and the lower 16 bits will be
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* in r1. */
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r1 += metonicCycle * (HALAKIM_PER_METONIC_CYCLE & 0xFFFF);
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r2 = r1 >> 16;
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r2 += metonicCycle * ((HALAKIM_PER_METONIC_CYCLE >> 16) & 0xFFFF);
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/* Calculate r2r1 / HALAKIM_PER_DAY. The remainder will be in r1, the
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* upper 16 bits of the quotient will be in d2 and the lower 16 bits
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* will be in d1. */
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d2 = r2 / HALAKIM_PER_DAY;
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r2 -= d2 * HALAKIM_PER_DAY;
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r1 = (r2 << 16) | (r1 & 0xFFFF);
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d1 = r1 / HALAKIM_PER_DAY;
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r1 -= d1 * HALAKIM_PER_DAY;
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*pMoladDay = (d2 << 16) | d1;
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*pMoladHalakim = r1;
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}
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/************************************************************************
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* Given a day number, find the molad of Tishri (the new moon at the start
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* of a year) which is closest to that day number. It's not really the
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* *closest* molad that we want here. If the input day is in the first two
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* months, we want the molad at the start of the year. If the input day is
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* in the fourth to last months, we want the molad at the end of the year.
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* If the input day is in the third month, it doesn't matter which molad is
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* returned, because both will be required. This type of "rounding" allows
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* us to avoid calculating the length of the year in most cases.
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*/
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static void FindTishriMolad(
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long int inputDay,
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int *pMetonicCycle,
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int *pMetonicYear,
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long int *pMoladDay,
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long int *pMoladHalakim)
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{
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long int moladDay;
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long int moladHalakim;
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int metonicCycle;
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int metonicYear;
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/* Estimate the metonic cycle number. Note that this may be an under
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* estimate because there are 6939.6896 days in a metonic cycle not
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* 6940, but it will never be an over estimate. The loop below will
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* correct for any error in this estimate. */
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metonicCycle = (inputDay + 310) / 6940;
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/* Calculate the time of the starting molad for this metonic cycle. */
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MoladOfMetonicCycle(metonicCycle, &moladDay, &moladHalakim);
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/* If the above was an under estimate, increment the cycle number until
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* the correct one is found. For modern dates this loop is about 98.6%
|
||
* likely to not execute, even once, because the above estimate is
|
||
* really quite close. */
|
||
while (moladDay < inputDay - 6940 + 310) {
|
||
metonicCycle++;
|
||
moladHalakim += HALAKIM_PER_METONIC_CYCLE;
|
||
moladDay += moladHalakim / HALAKIM_PER_DAY;
|
||
moladHalakim = moladHalakim % HALAKIM_PER_DAY;
|
||
}
|
||
|
||
/* Find the molad of Tishri closest to this date. */
|
||
for (metonicYear = 0; metonicYear < 18; metonicYear++) {
|
||
if (moladDay > inputDay - 74) {
|
||
break;
|
||
}
|
||
moladHalakim += HALAKIM_PER_LUNAR_CYCLE * monthsPerYear[metonicYear];
|
||
moladDay += moladHalakim / HALAKIM_PER_DAY;
|
||
moladHalakim = moladHalakim % HALAKIM_PER_DAY;
|
||
}
|
||
|
||
*pMetonicCycle = metonicCycle;
|
||
*pMetonicYear = metonicYear;
|
||
*pMoladDay = moladDay;
|
||
*pMoladHalakim = moladHalakim;
|
||
}
|
||
|
||
/************************************************************************
|
||
* Given a year, find the number of the first day of that year and the date
|
||
* and time of the starting molad.
|
||
*/
|
||
static void FindStartOfYear(
|
||
int year,
|
||
int *pMetonicCycle,
|
||
int *pMetonicYear,
|
||
long int *pMoladDay,
|
||
long int *pMoladHalakim,
|
||
int *pTishri1)
|
||
{
|
||
*pMetonicCycle = (year - 1) / 19;
|
||
*pMetonicYear = (year - 1) % 19;
|
||
MoladOfMetonicCycle(*pMetonicCycle, pMoladDay, pMoladHalakim);
|
||
|
||
*pMoladHalakim += HALAKIM_PER_LUNAR_CYCLE * yearOffset[*pMetonicYear];
|
||
*pMoladDay += *pMoladHalakim / HALAKIM_PER_DAY;
|
||
*pMoladHalakim = *pMoladHalakim % HALAKIM_PER_DAY;
|
||
|
||
*pTishri1 = Tishri1(*pMetonicYear, *pMoladDay, *pMoladHalakim);
|
||
}
|
||
|
||
/************************************************************************
|
||
* Given a serial day number (SDN), find the corresponding year, month and
|
||
* day in the Jewish calendar. The three output values will always be
|
||
* modified. If the input SDN is before the first day of year 1, they will
|
||
* all be set to zero, otherwise *pYear will be > 0; *pMonth will be in the
|
||
* range 1 to 13 inclusive; *pDay will be in the range 1 to 30 inclusive.
|
||
*/
|
||
void SdnToJewish(
|
||
long int sdn,
|
||
int *pYear,
|
||
int *pMonth,
|
||
int *pDay)
|
||
{
|
||
long int inputDay;
|
||
long int day;
|
||
long int halakim;
|
||
int metonicCycle;
|
||
int metonicYear;
|
||
int tishri1;
|
||
int tishri1After;
|
||
int yearLength;
|
||
|
||
if (sdn <= JEWISH_SDN_OFFSET) {
|
||
*pYear = 0;
|
||
*pMonth = 0;
|
||
*pDay = 0;
|
||
return;
|
||
}
|
||
inputDay = sdn - JEWISH_SDN_OFFSET;
|
||
|
||
FindTishriMolad(inputDay, &metonicCycle, &metonicYear, &day, &halakim);
|
||
tishri1 = Tishri1(metonicYear, day, halakim);
|
||
|
||
if (inputDay >= tishri1) {
|
||
/* It found Tishri 1 at the start of the year. */
|
||
*pYear = metonicCycle * 19 + metonicYear + 1;
|
||
if (inputDay < tishri1 + 59) {
|
||
if (inputDay < tishri1 + 30) {
|
||
*pMonth = 1;
|
||
*pDay = inputDay - tishri1 + 1;
|
||
} else {
|
||
*pMonth = 2;
|
||
*pDay = inputDay - tishri1 - 29;
|
||
}
|
||
return;
|
||
}
|
||
/* We need the length of the year to figure this out, so find
|
||
* Tishri 1 of the next year. */
|
||
halakim += HALAKIM_PER_LUNAR_CYCLE * monthsPerYear[metonicYear];
|
||
day += halakim / HALAKIM_PER_DAY;
|
||
halakim = halakim % HALAKIM_PER_DAY;
|
||
tishri1After = Tishri1((metonicYear + 1) % 19, day, halakim);
|
||
} else {
|
||
/* It found Tishri 1 at the end of the year. */
|
||
*pYear = metonicCycle * 19 + metonicYear;
|
||
if (inputDay >= tishri1 - 177) {
|
||
/* It is one of the last 6 months of the year. */
|
||
if (inputDay > tishri1 - 30) {
|
||
*pMonth = 13;
|
||
*pDay = inputDay - tishri1 + 30;
|
||
} else if (inputDay > tishri1 - 60) {
|
||
*pMonth = 12;
|
||
*pDay = inputDay - tishri1 + 60;
|
||
} else if (inputDay > tishri1 - 89) {
|
||
*pMonth = 11;
|
||
*pDay = inputDay - tishri1 + 89;
|
||
} else if (inputDay > tishri1 - 119) {
|
||
*pMonth = 10;
|
||
*pDay = inputDay - tishri1 + 119;
|
||
} else if (inputDay > tishri1 - 148) {
|
||
*pMonth = 9;
|
||
*pDay = inputDay - tishri1 + 148;
|
||
} else {
|
||
*pMonth = 8;
|
||
*pDay = inputDay - tishri1 + 178;
|
||
}
|
||
return;
|
||
} else {
|
||
if (monthsPerYear[(*pYear - 1) % 19] == 13) {
|
||
*pMonth = 7;
|
||
*pDay = inputDay - tishri1 + 207;
|
||
if (*pDay > 0)
|
||
return;
|
||
(*pMonth)--;
|
||
(*pDay) += 30;
|
||
if (*pDay > 0)
|
||
return;
|
||
(*pMonth)--;
|
||
(*pDay) += 30;
|
||
} else {
|
||
*pMonth = 6;
|
||
*pDay = inputDay - tishri1 + 207;
|
||
if (*pDay > 0)
|
||
return;
|
||
(*pMonth)--;
|
||
(*pDay) += 30;
|
||
}
|
||
if (*pDay > 0)
|
||
return;
|
||
(*pMonth)--;
|
||
(*pDay) += 29;
|
||
if (*pDay > 0)
|
||
return;
|
||
|
||
/* We need the length of the year to figure this out, so find
|
||
* Tishri 1 of this year. */
|
||
tishri1After = tishri1;
|
||
FindTishriMolad(day - 365,
|
||
&metonicCycle, &metonicYear, &day, &halakim);
|
||
tishri1 = Tishri1(metonicYear, day, halakim);
|
||
}
|
||
}
|
||
|
||
yearLength = tishri1After - tishri1;
|
||
day = inputDay - tishri1 - 29;
|
||
if (yearLength == 355 || yearLength == 385) {
|
||
/* Heshvan has 30 days */
|
||
if (day <= 30) {
|
||
*pMonth = 2;
|
||
*pDay = day;
|
||
return;
|
||
}
|
||
day -= 30;
|
||
} else {
|
||
/* Heshvan has 29 days */
|
||
if (day <= 29) {
|
||
*pMonth = 2;
|
||
*pDay = day;
|
||
return;
|
||
}
|
||
day -= 29;
|
||
}
|
||
|
||
/* It has to be Kislev. */
|
||
*pMonth = 3;
|
||
*pDay = day;
|
||
}
|
||
|
||
/************************************************************************
|
||
* Given a year, month and day in the Jewish calendar, find the
|
||
* corresponding serial day number (SDN). Zero is returned when the input
|
||
* date is detected as invalid. The return value will be > 0 for all valid
|
||
* dates, but there are some invalid dates that will return a positive
|
||
* value. To verify that a date is valid, convert it to SDN and then back
|
||
* and compare with the original.
|
||
*/
|
||
long int JewishToSdn(
|
||
int year,
|
||
int month,
|
||
int day)
|
||
{
|
||
long int sdn;
|
||
int metonicCycle;
|
||
int metonicYear;
|
||
int tishri1;
|
||
int tishri1After;
|
||
long int moladDay;
|
||
long int moladHalakim;
|
||
int yearLength;
|
||
int lengthOfAdarIAndII;
|
||
|
||
if (year <= 0 || day <= 0 || day > 30) {
|
||
return (0);
|
||
}
|
||
switch (month) {
|
||
case 1:
|
||
case 2:
|
||
/* It is Tishri or Heshvan - don't need the year length. */
|
||
FindStartOfYear(year, &metonicCycle, &metonicYear,
|
||
&moladDay, &moladHalakim, &tishri1);
|
||
if (month == 1) {
|
||
sdn = tishri1 + day - 1;
|
||
} else {
|
||
sdn = tishri1 + day + 29;
|
||
}
|
||
break;
|
||
|
||
case 3:
|
||
/* It is Kislev - must find the year length. */
|
||
|
||
/* Find the start of the year. */
|
||
FindStartOfYear(year, &metonicCycle, &metonicYear,
|
||
&moladDay, &moladHalakim, &tishri1);
|
||
|
||
/* Find the end of the year. */
|
||
moladHalakim += HALAKIM_PER_LUNAR_CYCLE * monthsPerYear[metonicYear];
|
||
moladDay += moladHalakim / HALAKIM_PER_DAY;
|
||
moladHalakim = moladHalakim % HALAKIM_PER_DAY;
|
||
tishri1After = Tishri1((metonicYear + 1) % 19, moladDay, moladHalakim);
|
||
|
||
yearLength = tishri1After - tishri1;
|
||
|
||
if (yearLength == 355 || yearLength == 385) {
|
||
sdn = tishri1 + day + 59;
|
||
} else {
|
||
sdn = tishri1 + day + 58;
|
||
}
|
||
break;
|
||
|
||
case 4:
|
||
case 5:
|
||
case 6:
|
||
/* It is Tevet, Shevat or Adar I - don't need the year length. */
|
||
|
||
FindStartOfYear(year + 1, &metonicCycle, &metonicYear,
|
||
&moladDay, &moladHalakim, &tishri1After);
|
||
|
||
if (monthsPerYear[(year - 1) % 19] == 12) {
|
||
lengthOfAdarIAndII = 29;
|
||
} else {
|
||
lengthOfAdarIAndII = 59;
|
||
}
|
||
|
||
if (month == 4) {
|
||
sdn = tishri1After + day - lengthOfAdarIAndII - 237;
|
||
} else if (month == 5) {
|
||
sdn = tishri1After + day - lengthOfAdarIAndII - 208;
|
||
} else {
|
||
sdn = tishri1After + day - lengthOfAdarIAndII - 178;
|
||
}
|
||
break;
|
||
|
||
default:
|
||
/* It is Adar II or later - don't need the year length. */
|
||
FindStartOfYear(year + 1, &metonicCycle, &metonicYear,
|
||
&moladDay, &moladHalakim, &tishri1After);
|
||
|
||
switch (month) {
|
||
case 7:
|
||
sdn = tishri1After + day - 207;
|
||
break;
|
||
case 8:
|
||
sdn = tishri1After + day - 178;
|
||
break;
|
||
case 9:
|
||
sdn = tishri1After + day - 148;
|
||
break;
|
||
case 10:
|
||
sdn = tishri1After + day - 119;
|
||
break;
|
||
case 11:
|
||
sdn = tishri1After + day - 89;
|
||
break;
|
||
case 12:
|
||
sdn = tishri1After + day - 60;
|
||
break;
|
||
case 13:
|
||
sdn = tishri1After + day - 30;
|
||
break;
|
||
default:
|
||
return (0);
|
||
}
|
||
}
|
||
return (sdn + JEWISH_SDN_OFFSET);
|
||
}
|
||
|
||
/*
|
||
* Local variables:
|
||
* tab-width: 4
|
||
* c-basic-offset: 4
|
||
* End:
|
||
* vim600: sw=4 ts=4 fdm=marker
|
||
* vim<600: sw=4 ts=4
|
||
*/
|