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Table for window sizes.
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@ -63,13 +63,84 @@
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/* TODO: optional Lim-Lee precomputation for the generator */
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/* this is just BN_window_bits_for_exponent_size from bn_lcl.h for now;
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* the table should be updated for EC */ /* TODO */
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#define EC_window_bits_for_scalar_size(b) \
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((b) > 671 ? 6 : \
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(b) > 239 ? 5 : \
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(b) > 79 ? 4 : \
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(b) > 23 ? 3 : 1)
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((b) >= 1500 ? 6 : \
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(b) >= 550 ? 5 : \
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(b) >= 200 ? 4 : \
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(b) >= 55 ? 3 : \
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(b) >= 20 ? 2 : \
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1)
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/* For window size 'w' (w >= 2), we compute the odd multiples
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* 1*P .. (2^w-1)*P.
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* This accounts for 2^(w-1) point additions (neglecting constants),
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* each of which requires 16 field multiplications (4 squarings
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* and 12 general multiplications) in the case of curves defined
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* over GF(p), which are the only curves we have so far.
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*
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* Converting these precomputed points into affine form takes
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* three field multiplications for inverting Z and one squaring
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* and three multiplications for adjusting X and Y, i.e.
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* 7 multiplications in total (1 squaring and 6 general multiplications),
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* again except for constants.
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*
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* The average number of windows for a 'b' bit scalar is roughly
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* b/(w+1).
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* Each of these windows (except possibly for the first one, but
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* we are ignoring constants anyway) requires one point addition.
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* As the precomputed table stores points in affine form, these
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* additions take only 11 field multiplications each (3 squarings
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* and 8 general multiplications).
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*
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* So the total workload, except for constants, is
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*
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* 2^(w-1)*[5 squarings + 18 multiplications]
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* + (b/(w+1))*[3 squarings + 8 multiplications]
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*
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* If we assume that 10 squarings are as costly as 9 multiplications,
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* our task is to find the 'w' that, given 'b', minimizes
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*
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* 2^(w-1)*(5*9 + 18*10) + (b/(w+1))*(3*9 + 8*10)
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* = 2^(w-1)*225 + (b/(w+1))*107.
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*
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* Thus optimal window sizes should be roughly as follows:
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*
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* w >= 6 if b >= 1414
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* w = 5 if 1413 >= b >= 505
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* w = 4 if 504 >= b >= 169
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* w = 3 if 168 >= b >= 51
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* w = 2 if 50 >= b >= 13
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* w = 1 if 12 >= b
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*
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* If we assume instead that squarings are exactly as costly as
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* multiplications, we have to minimize
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* 2^(w-1)*23 + (b/(w+1))*11.
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*
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* This gives us the following (nearly unchanged) table of optimal
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* windows sizes:
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*
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* w >= 6 if b >= 1406
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* w = 5 if 1405 >= b >= 502
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* w = 4 if 501 >= b >= 168
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* w = 3 if 167 >= b >= 51
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* w = 2 if 50 >= b >= 13
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* w = 1 if 12 >= b
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*
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* Note that neither table tries to take into account memory usage
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* (code locality etc.). Actual timings with NIST curve P-192 and
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* 192-bit scalars show that w = 3 (instead of 4) is preferrable;
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* and timings with NIST curve P-521 and 521-bit scalars show that
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* w = 4 (instead of 5) is preferrable. So we round up all the
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* boundaries and use the following table:
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*
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* w >= 6 if b >= 1500
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* w = 5 if 1499 >= b >= 550
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* w = 4 if 549 >= b >= 200
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* w = 3 if 199 >= b >= 55
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* w = 2 if 54 >= b >= 20
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* w = 1 if 19 >= b
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*/
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/* Compute
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* \sum scalars[i]*points[i]
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