mirror of
https://github.com/git/git.git
synced 2024-12-05 07:53:59 +08:00
ea82b2a085
When parsing a tree, we read the object ID directly out of the tree buffer. This is normally fine, but such an object ID cannot be used with oidcpy, which copies GIT_MAX_RAWSZ bytes, because if we are using SHA-1, there may not be that many bytes to copy. Instead, store the object ID in a separate struct member. Since we can no longer efficiently compute the path length, store that information as well in struct name_entry. Ensure we only copy the object ID into the new buffer if the path length is nonzero, as some callers will pass us an empty path with no object ID following it, and we will not want to read past the end of the buffer. Signed-off-by: brian m. carlson <sandals@crustytoothpaste.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
366 lines
8.6 KiB
C
366 lines
8.6 KiB
C
#include "cache.h"
|
|
#include "tree.h"
|
|
#include "tree-walk.h"
|
|
#include "object-store.h"
|
|
|
|
static int score_missing(unsigned mode, const char *path)
|
|
{
|
|
int score;
|
|
|
|
if (S_ISDIR(mode))
|
|
score = -1000;
|
|
else if (S_ISLNK(mode))
|
|
score = -500;
|
|
else
|
|
score = -50;
|
|
return score;
|
|
}
|
|
|
|
static int score_differs(unsigned mode1, unsigned mode2, const char *path)
|
|
{
|
|
int score;
|
|
|
|
if (S_ISDIR(mode1) != S_ISDIR(mode2))
|
|
score = -100;
|
|
else if (S_ISLNK(mode1) != S_ISLNK(mode2))
|
|
score = -50;
|
|
else
|
|
score = -5;
|
|
return score;
|
|
}
|
|
|
|
static int score_matches(unsigned mode1, unsigned mode2, const char *path)
|
|
{
|
|
int score;
|
|
|
|
/* Heh, we found SHA-1 collisions between different kind of objects */
|
|
if (S_ISDIR(mode1) != S_ISDIR(mode2))
|
|
score = -100;
|
|
else if (S_ISLNK(mode1) != S_ISLNK(mode2))
|
|
score = -50;
|
|
|
|
else if (S_ISDIR(mode1))
|
|
score = 1000;
|
|
else if (S_ISLNK(mode1))
|
|
score = 500;
|
|
else
|
|
score = 250;
|
|
return score;
|
|
}
|
|
|
|
static void *fill_tree_desc_strict(struct tree_desc *desc,
|
|
const struct object_id *hash)
|
|
{
|
|
void *buffer;
|
|
enum object_type type;
|
|
unsigned long size;
|
|
|
|
buffer = read_object_file(hash, &type, &size);
|
|
if (!buffer)
|
|
die("unable to read tree (%s)", oid_to_hex(hash));
|
|
if (type != OBJ_TREE)
|
|
die("%s is not a tree", oid_to_hex(hash));
|
|
init_tree_desc(desc, buffer, size);
|
|
return buffer;
|
|
}
|
|
|
|
static int base_name_entries_compare(const struct name_entry *a,
|
|
const struct name_entry *b)
|
|
{
|
|
return base_name_compare(a->path, tree_entry_len(a), a->mode,
|
|
b->path, tree_entry_len(b), b->mode);
|
|
}
|
|
|
|
/*
|
|
* Inspect two trees, and give a score that tells how similar they are.
|
|
*/
|
|
static int score_trees(const struct object_id *hash1, const struct object_id *hash2)
|
|
{
|
|
struct tree_desc one;
|
|
struct tree_desc two;
|
|
void *one_buf = fill_tree_desc_strict(&one, hash1);
|
|
void *two_buf = fill_tree_desc_strict(&two, hash2);
|
|
int score = 0;
|
|
|
|
for (;;) {
|
|
int cmp;
|
|
|
|
if (one.size && two.size)
|
|
cmp = base_name_entries_compare(&one.entry, &two.entry);
|
|
else if (one.size)
|
|
/* two lacks this entry */
|
|
cmp = -1;
|
|
else if (two.size)
|
|
/* two has more entries */
|
|
cmp = 1;
|
|
else
|
|
break;
|
|
|
|
if (cmp < 0) {
|
|
/* path1 does not appear in two */
|
|
score += score_missing(one.entry.mode, one.entry.path);
|
|
update_tree_entry(&one);
|
|
} else if (cmp > 0) {
|
|
/* path2 does not appear in one */
|
|
score += score_missing(two.entry.mode, two.entry.path);
|
|
update_tree_entry(&two);
|
|
} else {
|
|
/* path appears in both */
|
|
if (!oideq(&one.entry.oid, &two.entry.oid)) {
|
|
/* they are different */
|
|
score += score_differs(one.entry.mode,
|
|
two.entry.mode,
|
|
one.entry.path);
|
|
} else {
|
|
/* same subtree or blob */
|
|
score += score_matches(one.entry.mode,
|
|
two.entry.mode,
|
|
one.entry.path);
|
|
}
|
|
update_tree_entry(&one);
|
|
update_tree_entry(&two);
|
|
}
|
|
}
|
|
free(one_buf);
|
|
free(two_buf);
|
|
return score;
|
|
}
|
|
|
|
/*
|
|
* Match one itself and its subtrees with two and pick the best match.
|
|
*/
|
|
static void match_trees(const struct object_id *hash1,
|
|
const struct object_id *hash2,
|
|
int *best_score,
|
|
char **best_match,
|
|
const char *base,
|
|
int recurse_limit)
|
|
{
|
|
struct tree_desc one;
|
|
void *one_buf = fill_tree_desc_strict(&one, hash1);
|
|
|
|
while (one.size) {
|
|
const char *path;
|
|
const struct object_id *elem;
|
|
unsigned mode;
|
|
int score;
|
|
|
|
elem = tree_entry_extract(&one, &path, &mode);
|
|
if (!S_ISDIR(mode))
|
|
goto next;
|
|
score = score_trees(elem, hash2);
|
|
if (*best_score < score) {
|
|
free(*best_match);
|
|
*best_match = xstrfmt("%s%s", base, path);
|
|
*best_score = score;
|
|
}
|
|
if (recurse_limit) {
|
|
char *newbase = xstrfmt("%s%s/", base, path);
|
|
match_trees(elem, hash2, best_score, best_match,
|
|
newbase, recurse_limit - 1);
|
|
free(newbase);
|
|
}
|
|
|
|
next:
|
|
update_tree_entry(&one);
|
|
}
|
|
free(one_buf);
|
|
}
|
|
|
|
/*
|
|
* A tree "oid1" has a subdirectory at "prefix". Come up with a tree object by
|
|
* replacing it with another tree "oid2".
|
|
*/
|
|
static int splice_tree(const struct object_id *oid1, const char *prefix,
|
|
const struct object_id *oid2, struct object_id *result)
|
|
{
|
|
char *subpath;
|
|
int toplen;
|
|
char *buf;
|
|
unsigned long sz;
|
|
struct tree_desc desc;
|
|
unsigned char *rewrite_here;
|
|
const struct object_id *rewrite_with;
|
|
struct object_id subtree;
|
|
enum object_type type;
|
|
int status;
|
|
|
|
subpath = strchrnul(prefix, '/');
|
|
toplen = subpath - prefix;
|
|
if (*subpath)
|
|
subpath++;
|
|
|
|
buf = read_object_file(oid1, &type, &sz);
|
|
if (!buf)
|
|
die("cannot read tree %s", oid_to_hex(oid1));
|
|
init_tree_desc(&desc, buf, sz);
|
|
|
|
rewrite_here = NULL;
|
|
while (desc.size) {
|
|
const char *name;
|
|
unsigned mode;
|
|
|
|
tree_entry_extract(&desc, &name, &mode);
|
|
if (strlen(name) == toplen &&
|
|
!memcmp(name, prefix, toplen)) {
|
|
if (!S_ISDIR(mode))
|
|
die("entry %s in tree %s is not a tree", name,
|
|
oid_to_hex(oid1));
|
|
|
|
/*
|
|
* We cast here for two reasons:
|
|
*
|
|
* - to flip the "char *" (for the path) to "unsigned
|
|
* char *" (for the hash stored after it)
|
|
*
|
|
* - to discard the "const"; this is OK because we
|
|
* know it points into our non-const "buf"
|
|
*/
|
|
rewrite_here = (unsigned char *)(desc.entry.path +
|
|
strlen(desc.entry.path) +
|
|
1);
|
|
break;
|
|
}
|
|
update_tree_entry(&desc);
|
|
}
|
|
if (!rewrite_here)
|
|
die("entry %.*s not found in tree %s", toplen, prefix,
|
|
oid_to_hex(oid1));
|
|
if (*subpath) {
|
|
struct object_id tree_oid;
|
|
hashcpy(tree_oid.hash, rewrite_here);
|
|
status = splice_tree(&tree_oid, subpath, oid2, &subtree);
|
|
if (status)
|
|
return status;
|
|
rewrite_with = &subtree;
|
|
} else {
|
|
rewrite_with = oid2;
|
|
}
|
|
hashcpy(rewrite_here, rewrite_with->hash);
|
|
status = write_object_file(buf, sz, tree_type, result);
|
|
free(buf);
|
|
return status;
|
|
}
|
|
|
|
/*
|
|
* We are trying to come up with a merge between one and two that
|
|
* results in a tree shape similar to one. The tree two might
|
|
* correspond to a subtree of one, in which case it needs to be
|
|
* shifted down by prefixing otherwise empty directories. On the
|
|
* other hand, it could cover tree one and we might need to pick a
|
|
* subtree of it.
|
|
*/
|
|
void shift_tree(const struct object_id *hash1,
|
|
const struct object_id *hash2,
|
|
struct object_id *shifted,
|
|
int depth_limit)
|
|
{
|
|
char *add_prefix;
|
|
char *del_prefix;
|
|
int add_score, del_score;
|
|
|
|
/*
|
|
* NEEDSWORK: this limits the recursion depth to hardcoded
|
|
* value '2' to avoid excessive overhead.
|
|
*/
|
|
if (!depth_limit)
|
|
depth_limit = 2;
|
|
|
|
add_score = del_score = score_trees(hash1, hash2);
|
|
add_prefix = xcalloc(1, 1);
|
|
del_prefix = xcalloc(1, 1);
|
|
|
|
/*
|
|
* See if one's subtree resembles two; if so we need to prefix
|
|
* two with a few fake trees to match the prefix.
|
|
*/
|
|
match_trees(hash1, hash2, &add_score, &add_prefix, "", depth_limit);
|
|
|
|
/*
|
|
* See if two's subtree resembles one; if so we need to
|
|
* pick only subtree of two.
|
|
*/
|
|
match_trees(hash2, hash1, &del_score, &del_prefix, "", depth_limit);
|
|
|
|
/* Assume we do not have to do any shifting */
|
|
oidcpy(shifted, hash2);
|
|
|
|
if (add_score < del_score) {
|
|
/* We need to pick a subtree of two */
|
|
unsigned mode;
|
|
|
|
if (!*del_prefix)
|
|
return;
|
|
|
|
if (get_tree_entry(hash2, del_prefix, shifted, &mode))
|
|
die("cannot find path %s in tree %s",
|
|
del_prefix, oid_to_hex(hash2));
|
|
return;
|
|
}
|
|
|
|
if (!*add_prefix)
|
|
return;
|
|
|
|
splice_tree(hash1, add_prefix, hash2, shifted);
|
|
}
|
|
|
|
/*
|
|
* The user says the trees will be shifted by this much.
|
|
* Unfortunately we cannot fundamentally tell which one to
|
|
* be prefixed, as recursive merge can work in either direction.
|
|
*/
|
|
void shift_tree_by(const struct object_id *hash1,
|
|
const struct object_id *hash2,
|
|
struct object_id *shifted,
|
|
const char *shift_prefix)
|
|
{
|
|
struct object_id sub1, sub2;
|
|
unsigned mode1, mode2;
|
|
unsigned candidate = 0;
|
|
|
|
/* Can hash2 be a tree at shift_prefix in tree hash1? */
|
|
if (!get_tree_entry(hash1, shift_prefix, &sub1, &mode1) &&
|
|
S_ISDIR(mode1))
|
|
candidate |= 1;
|
|
|
|
/* Can hash1 be a tree at shift_prefix in tree hash2? */
|
|
if (!get_tree_entry(hash2, shift_prefix, &sub2, &mode2) &&
|
|
S_ISDIR(mode2))
|
|
candidate |= 2;
|
|
|
|
if (candidate == 3) {
|
|
/* Both are plausible -- we need to evaluate the score */
|
|
int best_score = score_trees(hash1, hash2);
|
|
int score;
|
|
|
|
candidate = 0;
|
|
score = score_trees(&sub1, hash2);
|
|
if (score > best_score) {
|
|
candidate = 1;
|
|
best_score = score;
|
|
}
|
|
score = score_trees(&sub2, hash1);
|
|
if (score > best_score)
|
|
candidate = 2;
|
|
}
|
|
|
|
if (!candidate) {
|
|
/* Neither is plausible -- do not shift */
|
|
oidcpy(shifted, hash2);
|
|
return;
|
|
}
|
|
|
|
if (candidate == 1)
|
|
/*
|
|
* shift tree2 down by adding shift_prefix above it
|
|
* to match tree1.
|
|
*/
|
|
splice_tree(hash1, shift_prefix, hash2, shifted);
|
|
else
|
|
/*
|
|
* shift tree2 up by removing shift_prefix from it
|
|
* to match tree1.
|
|
*/
|
|
oidcpy(shifted, &sub2);
|
|
}
|