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Let git-checkout always drop any detached head
We used to refuse leaving a detached HEAD when it wasn't matching an existing ref so not to lose any commit that might have been performed while not on any branch (unless -f was provided). But this protection was completely bogus since it was still possible to move to HEAD^ while still remaining detached but losing the last commit anyway if there was one. Now that we have a proper reflog for HEAD it is best to simply remove that bogus (and admitedly annoying) protection and simply display the last HEAD position instead. If one wants to recover a lost detached state then it can be retrieved from the HEAD reflog. Signed-off-by: Nicolas Pitre <nico@cam.org> Signed-off-by: Junio C Hamano <junkio@cox.net>
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@ -164,22 +164,9 @@ If you want to create a new branch from this checkout, you may do so
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(now or later) by using -b with the checkout command again. Example:
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git checkout -b <new_branch_name>"
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fi
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elif test -z "$oldbranch" && test -n "$branch"
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elif test -z "$oldbranch" && test -z "$quiet"
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then
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# Coming back...
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if test -z "$force"
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then
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git show-ref -d -s | grep "$old" >/dev/null || {
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echo >&2 \
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"You are not on any branch and switching to branch '$new_name'
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may lose your changes. At this point, you can do one of two things:
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(1) Decide it is Ok and say 'git checkout -f $new_name';
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(2) Start a new branch from the current commit, by saying
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'git checkout -b <branch-name>'.
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Leaving your HEAD detached; not switching to branch '$new_name'."
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exit 1;
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}
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fi
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echo >&2 "Previous HEAD position was $old"
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fi
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if [ "X$old" = X ]
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