cpython/Lib/test/test_module.py
Guido van Rossum c3a787e090 Surprising fix for SF bug 563060: module can be used as base class.
Change the module constructor (module_init) to have the signature
__init__(name:str, doc=None); this prevents the call from type_new()
to succeed.  While we're at it, prevent repeated calling of
module_init for the same module from leaking the dict, changing the
semantics so that __dict__ is only initialized if NULL.

Also adding a unittest, test_module.py.

This is an incompatibility with 2.2, if anybody was instantiating the
module class before, their argument list was probably empty; so this
can't be backported to 2.2.x.
2002-06-04 05:52:47 +00:00

49 lines
1.2 KiB
Python

# Test the module type
from test_support import verify, vereq, verbose, TestFailed
import sys
module = type(sys)
# An uninitialized module has no __dict__ or __name__, and __doc__ is None
foo = module.__new__(module)
verify(foo.__dict__ is None)
try:
s = foo.__name__
except AttributeError:
pass
else:
raise TestFailed, "__name__ = %s" % repr(s)
vereq(foo.__doc__, None)
# Regularly initialized module, no docstring
foo = module("foo")
vereq(foo.__name__, "foo")
vereq(foo.__doc__, None)
vereq(foo.__dict__, {"__name__": "foo", "__doc__": None})
# ASCII docstring
foo = module("foo", "foodoc")
vereq(foo.__name__, "foo")
vereq(foo.__doc__, "foodoc")
vereq(foo.__dict__, {"__name__": "foo", "__doc__": "foodoc"})
# Unicode docstring
foo = module("foo", u"foodoc\u1234")
vereq(foo.__name__, "foo")
vereq(foo.__doc__, u"foodoc\u1234")
vereq(foo.__dict__, {"__name__": "foo", "__doc__": u"foodoc\u1234"})
# Reinitialization should not replace the __dict__
foo.bar = 42
d = foo.__dict__
foo.__init__("foo", "foodoc")
vereq(foo.__name__, "foo")
vereq(foo.__doc__, "foodoc")
vereq(foo.bar, 42)
vereq(foo.__dict__, {"__name__": "foo", "__doc__": "foodoc", "bar": 42})
verify(foo.__dict__ is d)
if verbose:
print "All OK"