cpython/Lib/fnmatch.py
Guido van Rossum bdfcfccbe5 New == syntax
1992-01-01 19:35:13 +00:00

78 lines
1.7 KiB
Python

# module 'fnmatch' -- filename matching with shell patterns
def fnmatch(name, pat):
#
# Check for simple case: no special characters
#
if not ('*' in pat or '?' in pat or '[' in pat):
return name == pat
#
# Check for common cases: *suffix and prefix*
#
if pat[0] == '*':
p1 = pat[1:]
if not ('*' in p1 or '?' in p1 or '[' in p1):
start = len(name) - len(p1)
return start >= 0 and name[start:] == p1
elif pat[-1:] == '*':
p1 = pat[:-1]
if not ('*' in p1 or '?' in p1 or '[' in p1):
return name[:len(p1)] == p1
#
# General case
#
return fnmatch1(name, pat)
def fnmatch1(name, pat):
i, n = 0, len(pat)
while i < n:
c = pat[i]
if c == '*':
p1 = pat[i+1:]
if not ('*' in p1 or '?' in p1 or '[' in p1):
start = len(name) - len(p1)
return start >= 0 and name[start:] == p1
for i in range(i, len(name) + 1):
if fnmatch1(name[i:], p1):
return 1
return 0
elif c == '?':
if len(name) <= i : return 0
elif c == '[':
c, rest = name[i], name[i+1:]
i, n = i+1, len(pat) - 1
match = 0
exclude = 0
if i < n and pat[i] == '!':
exclude = 1
i = i+1
while i < n:
if pat[i] == c: match = 1
i = i+1
if i >= n or pat[i] == ']':
break
if pat[i] == '-':
i = i+1
if i >= n or pat[i] == ']':
break
if pat[i-2] <= c <= pat[i]:
match = 1
i = i+1
if i >= n or pat[i] == ']':
break
if match == exclude:
return 0
return fnmatch1(rest, pat[i+1:])
else:
if name[i:i+1] <> c:
return 0
i = i+1
# We don't get here if the pattern contained * or [...]
return i >= len(name)
def fnmatchlist(names, pat):
res = []
for name in names:
if fnmatch(name, pat): res.append(name)
return res