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load mod.submod as m, or mod as m ? Both can be achieved differently, and unambiguously. Also attempt to document this restriction (editor appreciated!) Note that this is an artificial check during compile, because incorporating this in the grammar is hard, and then adjusting the compiler to do the right thing with the right nodes is harder. |
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.cvsignore | ||
ref1.tex | ||
ref2.tex | ||
ref3.tex | ||
ref4.tex | ||
ref5.tex | ||
ref6.tex | ||
ref7.tex | ||
ref8.tex | ||
ref.tex | ||
reswords.py |