cpython/Lib/grep.py
Guido van Rossum 8566e474b4 Added pgrep() function, which is like grep/egrep/emgrep but uses Perl
syntax, by virtue of the new re module.
1997-10-22 20:44:58 +00:00

81 lines
1.8 KiB
Python

# 'grep'
import regex
from regex_syntax import *
import string
opt_show_where = 0
opt_show_filename = 0
opt_show_lineno = 1
def grep(pat, *files):
return ggrep(RE_SYNTAX_GREP, pat, files)
def egrep(pat, *files):
return ggrep(RE_SYNTAX_EGREP, pat, files)
def emgrep(pat, *files):
return ggrep(RE_SYNTAX_EMACS, pat, files)
def ggrep(syntax, pat, files):
if len(files) == 1 and type(files[0]) == type([]):
files = files[0]
global opt_show_filename
opt_show_filename = (len(files) != 1)
syntax = regex.set_syntax(syntax)
try:
prog = regex.compile(pat)
finally:
syntax = regex.set_syntax(syntax)
for filename in files:
fp = open(filename, 'r')
lineno = 0
while 1:
line = fp.readline()
if not line: break
lineno = lineno + 1
if prog.search(line) >= 0:
showline(filename, lineno, line, prog)
fp.close()
def pgrep(pat, *files):
if len(files) == 1 and type(files[0]) == type([]):
files = files[0]
global opt_show_filename
opt_show_filename = (len(files) != 1)
import re
prog = re.compile(pat)
for filename in files:
fp = open(filename, 'r')
lineno = 0
while 1:
line = fp.readline()
if not line: break
lineno = lineno + 1
if prog.search(line):
showline(filename, lineno, line, prog)
fp.close()
def showline(filename, lineno, line, prog):
if line[-1:] == '\n': line = line[:-1]
if opt_show_lineno:
prefix = string.rjust(`lineno`, 3) + ': '
else:
prefix = ''
if opt_show_filename:
prefix = filename + ': ' + prefix
print prefix + line
if opt_show_where:
start, end = prog.regs()[0]
line = line[:start]
if '\t' not in line:
prefix = ' ' * (len(prefix) + start)
else:
prefix = ' ' * len(prefix)
for c in line:
if c <> '\t': c = ' '
prefix = prefix + c
if start == end: prefix = prefix + '\\'
else: prefix = prefix + '^'*(end-start)
print prefix