Issue #11393: fix usage of locks in faulthandler

* faulthandler_cancel_dump_tracebacks_later() is responsible to set running
   to zero (so we don't need the volatile keyword anymore)
 * release locks if PyThread_start_new_thread() fails

assert(thread.running == 0) was wrong in a corner case
This commit is contained in:
Victor Stinner 2011-04-01 03:16:51 +02:00
parent a4d4f1b4cb
commit f309134eff

View File

@ -48,7 +48,7 @@ static struct {
int fd;
PY_TIMEOUT_T timeout_ms; /* timeout in microseconds */
int repeat;
volatile int running;
int running;
PyInterpreterState *interp;
int exit;
/* released by parent thread when cancel request */
@ -419,7 +419,6 @@ faulthandler_thread(void *unused)
/* The only way out */
PyThread_release_lock(thread.cancel_event);
PyThread_release_lock(thread.join_event);
thread.running = 0;
}
static void
@ -431,8 +430,8 @@ faulthandler_cancel_dump_tracebacks_later(void)
}
/* Wait for thread to join */
PyThread_acquire_lock(thread.join_event, 1);
assert(thread.running == 0);
PyThread_release_lock(thread.join_event);
thread.running = 0;
Py_CLEAR(thread.file);
}
@ -486,6 +485,8 @@ faulthandler_dump_traceback_later(PyObject *self,
thread.running = 1;
if (PyThread_start_new_thread(faulthandler_thread, NULL) == -1) {
thread.running = 0;
PyThread_release_lock(thread.join_event);
PyThread_release_lock(thread.cancel_event);
Py_CLEAR(thread.file);
PyErr_SetString(PyExc_RuntimeError,
"unable to start watchdog thread");