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added barrier test (by Tim Peters)
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@ -7,13 +7,18 @@ import thread
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import time
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mutex = thread.allocate_lock()
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whmutex = thread.allocate_lock() # for calls to whrandom
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running = 0
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done = thread.allocate_lock()
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done.acquire()
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numtasks = 10
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def task(ident):
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global running
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delay = whrandom.random() * 10
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whmutex.acquire()
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delay = whrandom.random() * numtasks
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whmutex.release()
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print 'task', ident, 'will run for', delay, 'sec'
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time.sleep(delay)
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print 'task', ident, 'done'
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@ -33,9 +38,69 @@ def newtask():
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running = running + 1
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mutex.release()
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for i in range(10):
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for i in range(numtasks):
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newtask()
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print 'waiting for all tasks to complete'
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done.acquire()
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print 'all tasks done'
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class barrier:
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def __init__(self, n):
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self.n = n
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self.waiting = 0
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self.checkin = thread.allocate_lock()
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self.checkout = thread.allocate_lock()
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self.checkout.acquire()
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def enter(self):
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checkin, checkout = self.checkin, self.checkout
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checkin.acquire()
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self.waiting = self.waiting + 1
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if self.waiting == self.n:
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self.waiting = self.n - 1
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checkout.release()
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return
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checkin.release()
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checkout.acquire()
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self.waiting = self.waiting - 1
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if self.waiting == 0:
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checkin.release()
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return
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checkout.release()
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numtrips = 3
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def task2(ident):
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global running
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for i in range(numtrips):
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if ident == 0:
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# give it a good chance to enter the next
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# barrier before the others are all out
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# of the current one
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delay = 0.001
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else:
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whmutex.acquire()
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delay = whrandom.random() * numtasks
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whmutex.release()
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print 'task', ident, 'will run for', delay, 'sec'
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time.sleep(delay)
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print 'task', ident, 'entering barrier', i
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bar.enter()
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print 'task', ident, 'leaving barrier', i
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mutex.acquire()
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running = running - 1
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if running == 0:
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done.release()
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mutex.release()
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print '\n*** Barrier Test ***'
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if done.acquire(0):
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raise ValueError, "'done' should have remained acquired"
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bar = barrier(numtasks)
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running = numtasks
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for i in range(numtasks):
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thread.start_new_thread(task2, (i,))
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done.acquire()
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print 'all tasks done'
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