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Simplify heapreplace() -- there's no need for an explicit test for
empty heap, since heap[0] raises the appropriate IndexError already.
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11
Lib/heapq.py
11
Lib/heapq.py
@ -150,13 +150,10 @@ def heapreplace(heap, item):
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returned may be larger than item! That constrains reasonable uses of
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this routine.
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"""
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if heap:
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returnitem = heap[0]
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heap[0] = item
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_siftup(heap, 0)
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return returnitem
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heap.pop() # raise IndexError
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returnitem = heap[0] # raises appropriate IndexError if heap is empty
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heap[0] = item
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_siftup(heap, 0)
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return returnitem
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def heapify(x):
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"""Transform list into a heap, in-place, in O(len(heap)) time."""
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