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Bugfix: Properly test for errors from PyLong_AsLong() in itertools.cycle.

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ti can raise an exception even if PyLong_Check() has
succeeded.
This commit is contained in:
Kristjan Valur Jonsson 2011-03-30 11:04:28 +00:00
parent ad45bfe2d3
commit 35722a9376
2 changed files with 11 additions and 3 deletions
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5
Lib/test/test_itertools.py
View File

@ -339,6 +339,8 @@ class TestBasicOps(unittest.TestCase):
list(range(maxsize-5, maxsize+5)))
self.assertEqual(list(islice(count(-maxsize-5), 10)),
list(range(-maxsize-5, -maxsize+5)))
self.assertEqual(list(islice(count(10, maxsize+5), 3)),
list(range(10, 10+3*(maxsize+5), maxsize+5)))
c = count(3)
self.assertEqual(repr(c), 'count(3)')
next(c)
@ -361,6 +363,9 @@ class TestBasicOps(unittest.TestCase):
self.assertEqual(next(copy.deepcopy(c)), value)
self.assertEqual(next(pickle.loads(pickle.dumps(c))), value)
#check proper internal error handling for large "step' sizes
count(1, maxsize+5); sys.exc_info()
def test_count_with_stride(self):
self.assertEqual(lzip('abc',count(2,3)), [('a', 2), ('b', 5), ('c', 8)])
self.assertEqual(lzip('abc',count(start=2,step=3)),

9
Modules/itertoolsmodule.c
View File

@ -2918,6 +2918,7 @@ count_new(PyTypeObject *type, PyObject *args, PyObject *kwds)
Py_ssize_t cnt = 0;
PyObject *long_cnt = NULL;
PyObject *long_step = NULL;
long step;
static char *kwlist[] = {"start", "step", 0};
if (!PyArg_ParseTupleAndKeywords(args, kwds, "|OO:count",
@ -2955,9 +2956,11 @@ count_new(PyTypeObject *type, PyObject *args, PyObject *kwds)
assert(long_cnt != NULL && long_step != NULL);
/* Fast mode only works when the step is 1 */
if (!PyLong_Check(long_step) ||
PyLong_AS_LONG(long_step) != 1) {
slow_mode = 1;
step = PyLong_AsLong(long_step);
if (step != 1) {
slow_mode = 1;
if (step == -1 && PyErr_Occurred())
PyErr_Clear();
}
if (slow_mode)