2002-08-03 02:29:53 +08:00
|
|
|
"""Unittests for heapq."""
|
|
|
|
|
|
|
|
from test.test_support import verify, vereq, verbose, TestFailed
|
|
|
|
|
2002-08-03 18:10:10 +08:00
|
|
|
from heapq import heappush, heappop, heapify, heapreplace
|
2002-08-03 02:29:53 +08:00
|
|
|
import random
|
|
|
|
|
|
|
|
def check_invariant(heap):
|
|
|
|
# Check the heap invariant.
|
|
|
|
for pos, item in enumerate(heap):
|
2002-08-03 03:41:54 +08:00
|
|
|
if pos: # pos 0 has no parent
|
|
|
|
parentpos = (pos-1) >> 1
|
2002-08-03 02:29:53 +08:00
|
|
|
verify(heap[parentpos] <= item)
|
|
|
|
|
2002-08-03 10:11:26 +08:00
|
|
|
# An iterator returning a heap's elements, smallest-first.
|
|
|
|
class heapiter(object):
|
|
|
|
def __init__(self, heap):
|
|
|
|
self.heap = heap
|
|
|
|
|
|
|
|
def next(self):
|
|
|
|
try:
|
|
|
|
return heappop(self.heap)
|
|
|
|
except IndexError:
|
|
|
|
raise StopIteration
|
|
|
|
|
|
|
|
def __iter__(self):
|
|
|
|
return self
|
|
|
|
|
2002-08-03 02:29:53 +08:00
|
|
|
def test_main():
|
|
|
|
# 1) Push 100 random numbers and pop them off, verifying all's OK.
|
|
|
|
heap = []
|
|
|
|
data = []
|
|
|
|
check_invariant(heap)
|
|
|
|
for i in range(256):
|
|
|
|
item = random.random()
|
|
|
|
data.append(item)
|
|
|
|
heappush(heap, item)
|
|
|
|
check_invariant(heap)
|
|
|
|
results = []
|
|
|
|
while heap:
|
|
|
|
item = heappop(heap)
|
|
|
|
check_invariant(heap)
|
|
|
|
results.append(item)
|
|
|
|
data_sorted = data[:]
|
|
|
|
data_sorted.sort()
|
|
|
|
vereq(data_sorted, results)
|
|
|
|
# 2) Check that the invariant holds for a sorted array
|
|
|
|
check_invariant(results)
|
|
|
|
# 3) Naive "N-best" algorithm
|
|
|
|
heap = []
|
|
|
|
for item in data:
|
|
|
|
heappush(heap, item)
|
|
|
|
if len(heap) > 10:
|
|
|
|
heappop(heap)
|
|
|
|
heap.sort()
|
|
|
|
vereq(heap, data_sorted[-10:])
|
2002-08-03 05:48:06 +08:00
|
|
|
# 4) Test heapify.
|
|
|
|
for size in range(30):
|
|
|
|
heap = [random.random() for dummy in range(size)]
|
|
|
|
heapify(heap)
|
|
|
|
check_invariant(heap)
|
|
|
|
# 5) Less-naive "N-best" algorithm, much faster (if len(data) is big
|
|
|
|
# enough <wink>) than sorting all of data. However, if we had a max
|
2002-08-03 10:11:26 +08:00
|
|
|
# heap instead of a min heap, it could go faster still via
|
2002-08-03 05:48:06 +08:00
|
|
|
# heapify'ing all of data (linear time), then doing 10 heappops
|
|
|
|
# (10 log-time steps).
|
|
|
|
heap = data[:10]
|
|
|
|
heapify(heap)
|
|
|
|
for item in data[10:]:
|
2002-08-03 10:11:26 +08:00
|
|
|
if item > heap[0]: # this gets rarer the longer we run
|
2002-08-03 18:10:10 +08:00
|
|
|
heapreplace(heap, item)
|
2002-08-03 10:11:26 +08:00
|
|
|
vereq(list(heapiter(heap)), data_sorted[-10:])
|
2002-12-07 18:33:42 +08:00
|
|
|
# 6) Exercise everything with repeated heapsort checks
|
|
|
|
for trial in xrange(100):
|
|
|
|
size = random.randrange(50)
|
|
|
|
data = [random.randrange(25) for i in range(size)]
|
|
|
|
if trial & 1: # Half of the time, use heapify
|
|
|
|
heap = data[:]
|
|
|
|
heapify(heap)
|
|
|
|
else: # The rest of the time, use heappush
|
|
|
|
heap = []
|
|
|
|
for item in data:
|
|
|
|
heappush(heap,item)
|
|
|
|
data.sort()
|
|
|
|
sorted = [heappop(heap) for i in range(size)]
|
|
|
|
vereq(data, sorted)
|
2002-08-03 02:29:53 +08:00
|
|
|
# Make user happy
|
|
|
|
if verbose:
|
|
|
|
print "All OK"
|
|
|
|
|
|
|
|
if __name__ == "__main__":
|
|
|
|
test_main()
|