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112efa81f2
`(exit N); exit N'. Otherwise, those many tests could exit with improper exit status when exiting via e.g., a trapped interrupt. Thanks to a report from Bob Proulx.
57 lines
1.3 KiB
Bash
Executable File
57 lines
1.3 KiB
Bash
Executable File
#!/bin/sh
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# ad-hoc tests of chgrp with -R and -H or -L and symlinks
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if test "$VERBOSE" = yes; then
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set -x
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chgrp --version
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fi
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. $srcdir/../group-names
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pwd=`pwd`
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tmp=recurse.$$
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trap 'status=$?; cd $pwd; rm -rf $tmp && exit $status' 0
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trap '(exit $?); exit' 1 2 13 15
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framework_failure=0
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mkdir $tmp || framework_failure=1
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cd $tmp || framework_failure=1
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if test $framework_failure = 1; then
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echo 'failure in testing framework' 1>&2
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(exit 1); exit 1
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fi
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set _ $groups; shift
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g1=$1
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g2=$2
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fail=0
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# chgrp -R should not traverse a symlink to a directory.
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mkdir d e
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touch d/dd e/ee
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ln -s ../e d/s
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chgrp -R $g1 e/ee || fail=1
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# This should not should change the group of e/ee
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chgrp -R $g2 d
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set _ `ls -l e/ee`; g=$5; test "$g" = $g1 || fail=1
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# This must change the group of e/ee, since -L makes
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# chgrp traverse the symlink from d/s into e.
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chgrp -L -R $g2 d
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set _ `ls -l e/ee`; g=$5; test "$g" = $g2 || fail=1
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# This must *not* change the group of e/ee
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chgrp -H -R $g1 d
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set _ `ls -l e/ee`; g=$5; test "$g" = $g2 || fail=1
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ln -s d link
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# This shouldn't change the group of e/ee either.
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chgrp -H -R $g1 link || fail=1
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set _ `ls -l e/ee`; g=$5; test "$g" = $g2 || fail=1
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# But it *should* change d/dd.
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set _ `ls -l d/dd`; g=$5; test "$g" = $g1 || fail=1
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(exit $fail); exit $fail
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