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@ -1,6 +1,6 @@
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#!/bin/sh
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# Get modification time of a file or directory and pretty-print it.
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# Copyright 1995, 1996, 1997 Free Software Foundation, Inc.
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# Copyright (C) 1995, 1996, 1997, 2003 Free Software Foundation, Inc.
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# written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
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#
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# This program is free software; you can redistribute it and/or modify
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@ -30,24 +30,38 @@ export LC_ALL
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LC_TIME=C
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export LC_TIME
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# Get the extended ls output of the file or directory.
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# On HPUX /bin/sh, "set" interprets "-rw-r--r--" as options, so the "x" below.
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if ls -L /dev/null 1>/dev/null 2>&1; then
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set - x`ls -L -l -d $1`
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else
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set - x`ls -l -d $1`
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fi
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# The month is at least the fourth argument
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# (3 shifts here, the next inside the loop).
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shift
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shift
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shift
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save_arg1="$1"
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# Find the month. Next argument is day, followed by the year or time.
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# Find out how to get the extended ls output of a file or directory.
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if ls -L /dev/null 1>/dev/null 2>&1; then
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ls_command='ls -L -l -d'
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else
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ls_command='ls -l -d'
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fi
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# A `ls -l' line looks as follows on OS/2.
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# drwxrwx--- 0 Aug 11 2001 foo
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# This differs from Unix, which adds ownership information.
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# drwxrwx--- 2 root root 4096 Aug 11 2001 foo
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#
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# To find the date, we split the line on spaces and iterate on words
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# until we find a month. This cannot work with files whose owner is a
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# user named `Jan', or `Feb', etc. However, it's unlikely that `/'
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# will be owned by a user whose name is a month. So we first look at
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# the extended ls output of the root directory to decide how many
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# words should be skipped to get the date.
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# On HPUX /bin/sh, "set" interprets "-rw-r--r--" as options, so the "x" below.
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set - x`$ls_command /`
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# Find which argument is the month.
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month=
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command=
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until test $month
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do
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shift
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# Add another shift to the command.
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command="$command shift;"
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case $1 in
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Jan) month=January; nummonth=1;;
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Feb) month=February; nummonth=2;;
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@ -64,6 +78,28 @@ do
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esac
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done
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# Get the extended ls output of the file or directory.
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set - x`eval "$ls_command \"\$save_arg1\""`
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# Remove all preceding arguments
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eval $command
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# Get the month. Next argument is day, followed by the year or time.
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case $1 in
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Jan) month=January; nummonth=1;;
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Feb) month=February; nummonth=2;;
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Mar) month=March; nummonth=3;;
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Apr) month=April; nummonth=4;;
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May) month=May; nummonth=5;;
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Jun) month=June; nummonth=6;;
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Jul) month=July; nummonth=7;;
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Aug) month=August; nummonth=8;;
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Sep) month=September; nummonth=9;;
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Oct) month=October; nummonth=10;;
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Nov) month=November; nummonth=11;;
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Dec) month=December; nummonth=12;;
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esac
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day=$2
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# Here we have to deal with the problem that the ls output gives either
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