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Avoid exponential behavior in rust_evaluate_subexp
The STRUCTOP_STRUCT case in rust_evaluate_subexp would evaluate its LHS, and then, if it did not need Rust-specific treatment, it would back up and re-evaluate the entire STRUCTOP_STRUCT part of the expression using evaluate_subexp_standard. This yields exponential behavior and causes some expressions to evaluate extremely slowly. The fix is to simply do the needed work inline. This is PR rust/21483. ChangeLog 2017-05-12 Tom Tromey <tom@tromey.com> PR rust/21483: * rust-lang.c (rust_evaluate_subexp) <STRUCTOP_STRUCT>: Don't recurse, just call value_struct_elt directly.
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@ -1,3 +1,9 @@
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2017-05-12 Tom Tromey <tom@tromey.com>
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PR rust/21483:
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* rust-lang.c (rust_evaluate_subexp) <STRUCTOP_STRUCT>: Don't
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recurse, just call value_struct_elt directly.
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2017-05-12 Tom Tromey <tom@tromey.com>
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* rust-lang.c (rust_dump_subexp_body) <STRUCTOP_ANONYMOUS,
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@ -1762,7 +1762,7 @@ tuple structs, and tuple-like enum variants"));
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case STRUCTOP_STRUCT:
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{
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struct value* lhs;
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struct value *lhs;
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struct type *type;
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int tem, pc;
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@ -1771,16 +1771,14 @@ tuple structs, and tuple-like enum variants"));
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(*pos) += 3 + BYTES_TO_EXP_ELEM (tem + 1);
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lhs = evaluate_subexp (NULL_TYPE, exp, pos, noside);
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const char *field_name = &exp->elts[pc + 2].string;
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type = value_type (lhs);
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if (TYPE_CODE (type) == TYPE_CODE_UNION
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&& !rust_union_is_untagged (type))
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{
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int i, start;
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struct disr_info disr;
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struct type* variant_type;
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char* field_name;
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field_name = &exp->elts[pc + 2].string;
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struct type *variant_type;
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disr = rust_get_disr_info (type, value_contents (lhs),
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value_embedded_offset (lhs),
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@ -1817,9 +1815,10 @@ which has only anonymous fields"),
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}
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else
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{
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/* Field access in structs and untagged unions works like C. */
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*pos = pc;
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result = evaluate_subexp_standard (expect_type, exp, pos, noside);
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result = value_struct_elt (&lhs, NULL, field_name, NULL,
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"structure");
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if (noside == EVAL_AVOID_SIDE_EFFECTS)
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result = value_zero (value_type (result), VALUE_LVAL (result));
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}
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}
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break;
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