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iomap: directly use logical block size
Don't transform the logical block size to a bit shift only to shift it back to the original block size. Just use the size. Cc: Christoph Hellwig <hch@lst.de> Reviewed-by: Chaitanya Kulkarni <kch@nvidia.com> Reviewed-by: Darrick J. Wong <djwong@kernel.org> Reviewed-by: Bart Van Assche <bvanassche@acm.org> Signed-off-by: Keith Busch <kbusch@kernel.org> Signed-off-by: Darrick J. Wong <djwong@kernel.org> Reviewed-by: Matthew Wilcox (Oracle) <willy@infradead.org> Reviewed-by: Christoph Hellwig <hch@lst.de>
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@ -240,7 +240,6 @@ static loff_t iomap_dio_bio_iter(const struct iomap_iter *iter,
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{
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const struct iomap *iomap = &iter->iomap;
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struct inode *inode = iter->inode;
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unsigned int blkbits = blksize_bits(bdev_logical_block_size(iomap->bdev));
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unsigned int fs_block_size = i_blocksize(inode), pad;
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loff_t length = iomap_length(iter);
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loff_t pos = iter->pos;
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@ -252,7 +251,7 @@ static loff_t iomap_dio_bio_iter(const struct iomap_iter *iter,
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size_t copied = 0;
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size_t orig_count;
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if ((pos | length) & ((1 << blkbits) - 1) ||
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if ((pos | length) & (bdev_logical_block_size(iomap->bdev) - 1) ||
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!bdev_iter_is_aligned(iomap->bdev, dio->submit.iter))
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return -EINVAL;
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