be2iscsi: Remove unnecessary synchronize_irq() before free_irq()

Calling synchronize_irq() right before free_irq() is quite useless. On one
hand the IRQ can easily fire again before free_irq() is entered, on the
other hand free_irq() itself calls synchronize_irq() internally (in a race
condition free way), before any state associated with the IRQ is freed.

Patch was generated using the following semantic patch:
// <smpl>
@@
expression irq;
@@
-synchronize_irq(irq);
 free_irq(irq, ...);
// </smpl>

Signed-off-by: Lars-Peter Clausen <lars@metafoo.de>
Reviewed-by: Jitendra Bhivare <jitendra.bhivare@broadcom.com>
Signed-off-by: Martin K. Petersen <martin.petersen@oracle.com>
This commit is contained in:
Lars-Peter Clausen 2016-03-04 11:15:06 +01:00 committed by Martin K. Petersen
parent 4cd2459c06
commit e729b50307

View File

@ -5303,15 +5303,12 @@ static void beiscsi_quiesce(struct beiscsi_hba *phba,
if (phba->msix_enabled) {
for (i = 0; i <= phba->num_cpus; i++) {
msix_vec = phba->msix_entries[i].vector;
synchronize_irq(msix_vec);
free_irq(msix_vec, &phwi_context->be_eq[i]);
kfree(phba->msi_name[i]);
}
} else
if (phba->pcidev->irq) {
synchronize_irq(phba->pcidev->irq);
if (phba->pcidev->irq)
free_irq(phba->pcidev->irq, phba);
}
pci_disable_msix(phba->pcidev);
cancel_delayed_work_sync(&phba->beiscsi_hw_check_task);