hexdump: do not print debug dumps for !CONFIG_DEBUG

print_hex_dump_debug() is likely supposed to be analogous to pr_debug() or
dev_dbg() & friends.  Currently it will adhere to dynamic debug, but will
not stub out prints if CONFIG_DEBUG is not set.  Let's make it do the
right thing, because I am tired of having my dmesg buffer full of hex
dumps on production systems.

Signed-off-by: Linus Walleij <linus.walleij@linaro.org>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Linus Walleij 2015-09-09 15:37:11 -07:00 committed by Linus Torvalds
parent 9bf98f168b
commit cdf17449af

View File

@ -456,11 +456,17 @@ static inline void print_hex_dump_bytes(const char *prefix_str, int prefix_type,
groupsize, buf, len, ascii) \
dynamic_hex_dump(prefix_str, prefix_type, rowsize, \
groupsize, buf, len, ascii)
#else
#elif defined(DEBUG)
#define print_hex_dump_debug(prefix_str, prefix_type, rowsize, \
groupsize, buf, len, ascii) \
print_hex_dump(KERN_DEBUG, prefix_str, prefix_type, rowsize, \
groupsize, buf, len, ascii)
#endif /* defined(CONFIG_DYNAMIC_DEBUG) */
#else
static inline void print_hex_dump_debug(const char *prefix_str, int prefix_type,
int rowsize, int groupsize,
const void *buf, size_t len, bool ascii)
{
}
#endif
#endif