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hexdump: do not print debug dumps for !CONFIG_DEBUG
print_hex_dump_debug() is likely supposed to be analogous to pr_debug() or dev_dbg() & friends. Currently it will adhere to dynamic debug, but will not stub out prints if CONFIG_DEBUG is not set. Let's make it do the right thing, because I am tired of having my dmesg buffer full of hex dumps on production systems. Signed-off-by: Linus Walleij <linus.walleij@linaro.org> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -456,11 +456,17 @@ static inline void print_hex_dump_bytes(const char *prefix_str, int prefix_type,
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groupsize, buf, len, ascii) \
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dynamic_hex_dump(prefix_str, prefix_type, rowsize, \
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groupsize, buf, len, ascii)
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#else
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#elif defined(DEBUG)
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#define print_hex_dump_debug(prefix_str, prefix_type, rowsize, \
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groupsize, buf, len, ascii) \
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print_hex_dump(KERN_DEBUG, prefix_str, prefix_type, rowsize, \
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groupsize, buf, len, ascii)
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#endif /* defined(CONFIG_DYNAMIC_DEBUG) */
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#else
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static inline void print_hex_dump_debug(const char *prefix_str, int prefix_type,
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int rowsize, int groupsize,
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const void *buf, size_t len, bool ascii)
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{
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}
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#endif
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#endif
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