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erofs: clear compacted_2b if compacted_4b_initial > totalidx
Currently, the whole indexes will only be compacted 4B if compacted_4b_initial > totalidx. So, the calculated compacted_2b is worthless for that case. It may waste CPU resources. No need to update compacted_4b_initial as mkfs since it's used to fulfill the alignment of the 1st compacted_2b pack and would handle the case above. We also need to clarify compacted_4b_end here. It's used for the last lclusters which aren't fitted in the previous compacted_2b packs. Some messages are from Xiang. Link: https://lore.kernel.org/r/20210914035915.1190-1-zbestahu@gmail.com Signed-off-by: Yue Hu <huyue2@yulong.com> Reviewed-by: Gao Xiang <hsiangkao@linux.alibaba.com> Reviewed-by: Chao Yu <chao@kernel.org> [ Gao Xiang: it's enough to use "compacted_4b_initial < totalidx". ] Signed-off-by: Gao Xiang <hsiangkao@linux.alibaba.com>
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@ -369,7 +369,8 @@ static int compacted_load_cluster_from_disk(struct z_erofs_maprecorder *m,
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if (compacted_4b_initial == 32 / 4)
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compacted_4b_initial = 0;
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if (vi->z_advise & Z_EROFS_ADVISE_COMPACTED_2B)
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if ((vi->z_advise & Z_EROFS_ADVISE_COMPACTED_2B) &&
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compacted_4b_initial < totalidx)
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compacted_2b = rounddown(totalidx - compacted_4b_initial, 16);
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else
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compacted_2b = 0;
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