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ftrace: Optimize the allocation for mcount entries

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If we can't allocate this size, try something smaller with half of the
size. Its order should be decreased by one instead of divided by two.

Link: https://lkml.kernel.org/r/20221109094434.84046-3-wangwensheng4@huawei.com

Cc: <mhiramat@kernel.org>
Cc: <mark.rutland@arm.com>
Cc: stable@vger.kernel.org
Fixes: a790087554 ("ftrace: Allocate the mcount record pages as groups")
Signed-off-by: Wang Wensheng <wangwensheng4@huawei.com>
Signed-off-by: Steven Rostedt (Google) <rostedt@goodmis.org>
This commit is contained in:
Wang Wensheng 2022-11-09 09:44:33 +00:00 committed by Steven Rostedt (Google)
parent 08948caebe
commit bcea02b096
1 changed files with 1 additions and 1 deletions
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2
kernel/trace/ftrace.c
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@ -3190,7 +3190,7 @@ static int ftrace_allocate_records(struct ftrace_page *pg, int count)
/* if we can't allocate this size, try something smaller */
if (!order)
return -ENOMEM;
order >>= 1;
order--;
goto again;
}