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kexec: fix memory leak in function kimage_normal_alloc
If kimage_normal_alloc() fails to alloc pages for image->swap_page, it should call kimage_free_page_list() to free allocated pages in image->control_pages list before it frees image. Signed-off-by: Zhang Yanfei <zhangyanfei@cn.fujitsu.com> Cc: "Eric W. Biederman" <ebiederm@xmission.com> Cc: Sasha Levin <sasha.levin@oracle.com> Reviewed-by: Simon Horman <horms@verge.net.au> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -229,6 +229,8 @@ out:
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}
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static void kimage_free_page_list(struct list_head *list);
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static int kimage_normal_alloc(struct kimage **rimage, unsigned long entry,
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unsigned long nr_segments,
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struct kexec_segment __user *segments)
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@ -252,22 +254,22 @@ static int kimage_normal_alloc(struct kimage **rimage, unsigned long entry,
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get_order(KEXEC_CONTROL_PAGE_SIZE));
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if (!image->control_code_page) {
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printk(KERN_ERR "Could not allocate control_code_buffer\n");
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goto out;
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goto out_free;
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}
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image->swap_page = kimage_alloc_control_pages(image, 0);
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if (!image->swap_page) {
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printk(KERN_ERR "Could not allocate swap buffer\n");
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goto out;
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goto out_free;
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}
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result = 0;
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out:
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if (result == 0)
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*rimage = image;
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else
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kfree(image);
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*rimage = image;
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return 0;
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out_free:
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kimage_free_page_list(&image->control_pages);
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kfree(image);
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out:
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return result;
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}
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