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md: Don't wait UNINTERRUPTIBLE for other resync to finish

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When two md arrays share some block device (e.g each uses different
partitions on the one device), a resync of one array will wait for
the resync on the other to finish.

This can be a long time and as it currently waits TASK_UNINTERRUPTIBLE,
the softlockup code notices and complains.

So use TASK_INTERRUPTIBLE instead and make sure to flush signals
before calling schedule.

Signed-off-by: NeilBrown <neilb@suse.de>
This commit is contained in:
NeilBrown 2008-09-19 11:49:54 +10:00
parent 45e9c0de2e
commit 9744197c3d
1 changed files with 7 additions and 1 deletions
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8
drivers/md/md.c
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@ -5761,7 +5761,11 @@ void md_do_sync(mddev_t *mddev)
* time 'round when curr_resync == 2
*/
continue;
prepare_to_wait(&resync_wait, &wq, TASK_UNINTERRUPTIBLE);
/* We need to wait 'interruptible' so as not to
* contribute to the load average, and not to
* be caught by 'softlockup'
*/
prepare_to_wait(&resync_wait, &wq, TASK_INTERRUPTIBLE);
if (!kthread_should_stop() &&
mddev2->curr_resync >= mddev->curr_resync) {
printk(KERN_INFO "md: delaying %s of %s"
@ -5769,6 +5773,8 @@ void md_do_sync(mddev_t *mddev)
" share one or more physical units)\n",
desc, mdname(mddev), mdname(mddev2));
mddev_put(mddev2);
if (signal_pending(current))
flush_signals(current);
schedule();
finish_wait(&resync_wait, &wq);
goto try_again;