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[IA64] need r29=psr *after* rsm psr.i
Yanmin Zhang pointed out a sequence problem when saving the psr. David Mosberger provided this patch (which gave up a cycle). Signed-off-by: Tony Luck <tony.luck@intel.com>
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@ -77,7 +77,7 @@ GLOBAL_ENTRY(__kernel_syscall_via_epc)
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epc // B causes split-issue
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}
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;;
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rsm psr.be // M2 (5 cyc to srlz.d)
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rsm psr.be | psr.i // M2 (5 cyc to srlz.d)
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LOAD_FSYSCALL_TABLE(r14) // X
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;;
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mov r16=IA64_KR(CURRENT) // M2 (12 cyc)
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@ -98,15 +98,14 @@ GLOBAL_ENTRY(__kernel_syscall_via_epc)
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nop.i 0
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;;
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nop.m 0
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(p6) mov b7=r18 // I0
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(p6) tbit.z.unc p8,p0=r18,0 // I0 (dual-issues with "mov b7=r18"!)
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nop.m 0
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nop.i 0
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;;
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(p8) ssm psr.i
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(p6) mov b7=r18 // I0
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(p8) br.dptk.many b7 // B
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mov r27=ar.rsc // M2 (12 cyc)
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(p6) rsm psr.i // M2
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/*
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* brl.cond doesn't work as intended because the linker would convert this branch
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* into a branch to a PLT. Perhaps there will be a way to avoid this with some
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@ -123,7 +122,7 @@ GLOBAL_ENTRY(__kernel_syscall_via_epc)
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#else
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BRL_COND_FSYS_BUBBLE_DOWN(p6)
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#endif
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ssm psr.i
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mov r10=-1
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(p10) mov r8=EINVAL
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(p9) mov r8=ENOSYS
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