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i40e: avoid double calling i40e_pf_rxq_wait()

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Currently, when interface is being brought down and
i40e_vsi_stop_rings() is called, i40e_pf_rxq_wait() is called two times,
which is wrong. To showcase this scenario, simplified call stack looks
as follows:

i40e_vsi_stop_rings()
	i40e_control wait rx_q()
		i40e_control_rx_q()
		i40e_pf_rxq_wait()
	i40e_vsi_wait_queues_disabled()
		i40e_pf_rxq_wait()  // redundant call

To fix this, let us s/i40e_control_wait_rx_q/i40e_control_rx_q within
i40e_vsi_stop_rings().

Fixes: 65662a8dcd ("i40e: Fix logic of disabling queues")
Reviewed-by: Simon Horman <horms@kernel.org>
Signed-off-by: Maciej Fijalkowski <maciej.fijalkowski@intel.com>
Reviewed-by: Ivan Vecera <ivecera@redhat.com>
Tested-by: Chandan Kumar Rout <chandanx.rout@intel.com> (A Contingent Worker at Intel)
Signed-off-by: Tony Nguyen <anthony.l.nguyen@intel.com>
This commit is contained in:
Maciej Fijalkowski 2024-02-06 13:41:31 +01:00 committed by Tony Nguyen
parent 343bb39e1f
commit 89a373e913
1 changed files with 3 additions and 9 deletions
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12
drivers/net/ethernet/intel/i40e/i40e_main.c
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@ -4926,7 +4926,7 @@ int i40e_vsi_start_rings(struct i40e_vsi *vsi)
void i40e_vsi_stop_rings(struct i40e_vsi *vsi)
{
struct i40e_pf *pf = vsi->back;
int pf_q, err, q_end;
int pf_q, q_end;
/* When port TX is suspended, don't wait */
if (test_bit(__I40E_PORT_SUSPENDED, vsi->back->state))
@ -4936,16 +4936,10 @@ void i40e_vsi_stop_rings(struct i40e_vsi *vsi)
for (pf_q = vsi->base_queue; pf_q < q_end; pf_q++)
i40e_pre_tx_queue_cfg(&pf->hw, (u32)pf_q, false);
for (pf_q = vsi->base_queue; pf_q < q_end; pf_q++) {
err = i40e_control_wait_rx_q(pf, pf_q, false);
if (err)
dev_info(&pf->pdev->dev,
"VSI seid %d Rx ring %d disable timeout\n",
vsi->seid, pf_q);
}
for (pf_q = vsi->base_queue; pf_q < q_end; pf_q++)
i40e_control_rx_q(pf, pf_q, false);
msleep(I40E_DISABLE_TX_GAP_MSEC);
pf_q = vsi->base_queue;
for (pf_q = vsi->base_queue; pf_q < q_end; pf_q++)
wr32(&pf->hw, I40E_QTX_ENA(pf_q), 0);