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io-wq: fix wakeup race when adding new work
When new work is added, io_wqe_enqueue() checks if we need to wake or create a new worker. But that check is done outside the lock that otherwise synchronizes us with a worker going to sleep, so we can end up in the following situation: CPU0 CPU1 lock insert work unlock atomic_read(nr_running) != 0 lock atomic_dec(nr_running) no wakeup needed Hold the wqe lock around the "need to wakeup" check. Then we can also get rid of the temporary work_flags variable, as we know the work will remain valid as long as we hold the lock. Cc: stable@vger.kernel.org Reported-by: Andres Freund <andres@anarazel.de> Signed-off-by: Jens Axboe <axboe@kernel.dk>
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@ -794,7 +794,7 @@ append:
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static void io_wqe_enqueue(struct io_wqe *wqe, struct io_wq_work *work)
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{
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struct io_wqe_acct *acct = io_work_get_acct(wqe, work);
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int work_flags;
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bool do_wake;
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/*
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* If io-wq is exiting for this task, or if the request has explicitly
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@ -806,14 +806,14 @@ static void io_wqe_enqueue(struct io_wqe *wqe, struct io_wq_work *work)
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return;
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}
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work_flags = work->flags;
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raw_spin_lock(&wqe->lock);
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io_wqe_insert_work(wqe, work);
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wqe->flags &= ~IO_WQE_FLAG_STALLED;
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do_wake = (work->flags & IO_WQ_WORK_CONCURRENT) ||
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!atomic_read(&acct->nr_running);
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raw_spin_unlock(&wqe->lock);
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if ((work_flags & IO_WQ_WORK_CONCURRENT) ||
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!atomic_read(&acct->nr_running))
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if (do_wake)
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io_wqe_wake_worker(wqe, acct);
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}
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