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sched: Fix the place where group powers are updated

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We want to update the sched_group_powers when balance_cpu == this_cpu.

Currently the group powers are updated only if the balance_cpu is the
first CPU in the local group. But balance_cpu = this_cpu could also be
the first idle cpu in the group. Hence fix the place where the group
powers are updated.

Signed-off-by: Gautham R Shenoy <ego@in.ibm.com>
Signed-off-by: Joel Schopp <jschopp@austin.ibm.com>
Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl>
LKML-Reference: <1264017764.5717.127.camel@jschopp-laptop>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
This commit is contained in:
Gautham R Shenoy 2010-01-20 14:02:44 -06:00 committed by Ingo Molnar
parent 8f190fb3f7
commit 871e35bc97
1 changed files with 3 additions and 4 deletions
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7
kernel/sched_fair.c
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@ -2418,11 +2418,8 @@ static inline void update_sg_lb_stats(struct sched_domain *sd,
unsigned long sum_avg_load_per_task;
unsigned long avg_load_per_task;
if (local_group) {
if (local_group)
balance_cpu = group_first_cpu(group);
if (balance_cpu == this_cpu)
update_group_power(sd, this_cpu);
}
/* Tally up the load of all CPUs in the group */
sum_avg_load_per_task = avg_load_per_task = 0;
@ -2470,6 +2467,8 @@ static inline void update_sg_lb_stats(struct sched_domain *sd,
return;
}
update_group_power(sd, this_cpu);
/* Adjust by relative CPU power of the group */
sgs->avg_load = (sgs->group_load * SCHED_LOAD_SCALE) / group->cpu_power;