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x86/fpu: Move debugging check from kernel_fpu_begin() to __kernel_fpu_begin()
kernel_fpu_begin() is __kernel_fpu_begin() with a preempt_disable(). Move the kernel_fpu_begin() debugging check into __kernel_fpu_begin(), so that users of __kernel_fpu_begin() may benefit from it as well. Cc: Andy Lutomirski <luto@amacapital.net> Cc: Borislav Petkov <bp@alien8.de> Cc: Dave Hansen <dave.hansen@linux.intel.com> Cc: Fenghua Yu <fenghua.yu@intel.com> Cc: H. Peter Anvin <hpa@zytor.com> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Oleg Nesterov <oleg@redhat.com> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Thomas Gleixner <tglx@linutronix.de> Signed-off-by: Ingo Molnar <mingo@kernel.org>
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@ -109,6 +109,8 @@ void __kernel_fpu_begin(void)
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{
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struct fpu *fpu = ¤t->thread.fpu;
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WARN_ON_ONCE(!irq_fpu_usable());
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kernel_fpu_disable();
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if (fpu->fpregs_active) {
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@ -138,7 +140,6 @@ EXPORT_SYMBOL(__kernel_fpu_end);
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void kernel_fpu_begin(void)
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{
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preempt_disable();
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WARN_ON_ONCE(!irq_fpu_usable());
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__kernel_fpu_begin();
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}
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EXPORT_SYMBOL_GPL(kernel_fpu_begin);
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