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uglify while_each_pid_task() to make sure we don't count the execing pricess twice
There is a window when de_thread() switches the leader and drops tasklist_lock. In that window do_each_pid_task(PIDTYPE_PID) finds both new and old leaders. The problem is pretty much theoretical and probably can be ignored. Currently the only users of do_each_pid_task(PIDTYPE_PID) are send_sigio/send_sigurg, so they can send the signal to the same process twice. Signed-off-by: Oleg Nesterov <oleg@tv-sign.ru> Cc: "Eric W. Biederman" <ebiederm@xmission.com> Cc: Davide Libenzi <davidel@xmailserver.org> Cc: Pavel Emelyanov <xemul@openvz.org> Cc: Roland McGrath <roland@redhat.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -152,7 +152,13 @@ pid_t pid_vnr(struct pid *pid);
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hlist_for_each_entry_rcu((task), pos___, \
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&pid->tasks[type], pids[type].node) {
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/*
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* Both old and new leaders may be attached to
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* the same pid in the middle of de_thread().
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*/
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#define while_each_pid_task(pid, type, task) \
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if (type == PIDTYPE_PID) \
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break; \
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} \
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} while (0)
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