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sched: Remove useless code in yield_to()

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It's impossible to enter the else branch if we have set
skip_clock_update in task_yield_fair(), as yield_to_task_fair()
 will directly return true after invoke task_yield_fair().

Signed-off-by: Michael Wang <wangyun@linux.vnet.ibm.com>
Acked-by: Mike Galbraith <efault@gmx.de>
Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl>
Link: http://lkml.kernel.org/r/4FF2925A.9060005@linux.vnet.ibm.com
Signed-off-by: Ingo Molnar <mingo@kernel.org>
This commit is contained in:
Michael Wang 2012-07-03 14:34:02 +08:00 committed by Ingo Molnar
parent d00535db42
commit 38b8dd6f87
1 changed files with 0 additions and 7 deletions
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7
kernel/sched/core.c
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@ -4348,13 +4348,6 @@ again:
*/
if (preempt && rq != p_rq)
resched_task(p_rq->curr);
} else {
/*
* We might have set it in task_yield_fair(), but are
* not going to schedule(), so don't want to skip
* the next update.
*/
rq->skip_clock_update = 0;
}
out: